Regex for getting text between the last brackets ()

Question

I want to extract the text between the last () using javascript

For example

var someText="don't extract(value_a) but extract(value_b)";
alert(someText.match(regex));

The result should be

value_b

Thanks for the help

Answer 1

Try this

\(([^)]*)\)[^(]*$

See it here on regexr

var someText="don't extract(value_a) but extract(value_b)";
alert(someText.match(/\(([^)]*)\)[^(]*$/)[1]);

The part inside the brackets is stored in capture group 1, therefor you need to use match()[1] to access the result.

Answer 2

/\([^()]+\)(?=[^()]*$)/

前瞻(?=[^()]*$)断言在输入结束之前没有更多的括号。

Answer 3

An efficient solution is to let .* eat up everything before the last (

 var str = "don't extract(value_a) but extract(value_b)"; var res = str.match(/.*\\(([^)]+)\\)/)[1]; console.log(res); 

• .*\\( matches any amount of any character until the last literal (
• ([^)]+) captures one or more characters that are not )
• [1] grab captures of group 1 (first capturing group).
• use [\\s\\S] instead of . dot for multiline strings.

Here is a demo at regex101

Answer 4

If the last closing bracket is always at the end of the sentence, you can use Jonathans answer. Otherwise something like this might work:

/\((\w+)\)(?:(?!\(\w+\)).)*$/