Get the element in the array with the max value of a property using jQuery

Question

I have an array of a custom JavaScript object which has a property named order . I have an array of this object, and I want to get the item with the highest "order".

Since I'm relatively new to jQuery, and coming from a C# background this is one of the instances where I highly appreciate LINQ :)

Anyway, to cut a long story short, I've checked the following links but they only return the value and not a reference of the array element itself... So a little help in changing that to return the element would be appreciated.

jQuery min/max property from array of elements

element with the max height from a set of elements

The custom object in question(which I have an array of) is as follows:

var severity = function (key, value, order) {
    this.key = key;
    this.value = value;
    this.order = order;
};

Answer 1

Maybe I got you wrong... but is that you are looking for?

function getHighest(array) {
    var max = {};
    for (var i = 0; i < array.length; i++) {
        if (array[i].order > (max.order || 0))
            max = array[i];
    }
    return max;
}

// var array = [object, object, object ...];
var highest = getHighest(array);

DEMO: http://jsfiddle.net/c6gfj/

Answer 2

Sort array and pop the last object in array

function sortObj(a, b){
     return a.order < b.order ? 0 : 1;
}
obj.sort(sortObj)   
var highest =obj.pop();

DEMO: http://jsfiddle.net/VaYNb/

Answer 3

使用yourarray.sort（）。它将按升序降序排序。对二维数组也有效。

Answer 4

array[array.map((o)=>o.order).indexOf(Math.max(...array.map((o)=>o.order)))]

DEMO :

 let array=[{order:3},{order:5},{order:2},{order:2}]; console.log( array[array.map((o)=>o.order).indexOf(Math.max(...array.map((o)=>o.order)))] ) 

Answer 5

try this:

function getHighest(array, value){
  return array.sort(function(a,b){ b[value] - a[value] })[0];
}