SQL Server 2008 Compare two different database tables for column name, data type and length

Question

I am using SQL Server 2008 R2.

I have created two different databases Master and Test . Both of them have the same tables and columns in the beginning, but then master is used for some stable environment and test is used by me for ongoing development.

Now due to development I have changed some column's data types, added some new columns to the tables, deleted some columns, added some new tables and also deleted. Now I want to make Master same as test . I cannot drop and re-create Master as it contains some sensitive live data. So I need to compare each and every table of master with test along with column name, data type, constraints and length. Is there any solution?

Answer 1

Resolved it my self :

SELECT  
    T.[name] AS [table_name], AC.[name] AS [column_name],  
        TY.[name] AS system_data_type
FROM    [master].sys.[tables] AS T  
    INNER JOIN [master].sys.[all_columns] AC ON T.[object_id] = AC.[object_id] 
    INNER JOIN [master].sys.[types] TY ON AC.[system_type_id] = TY.[system_type_id]

EXCEPT

SELECT  
    T.[name] AS [table_name], AC.[name] AS [column_name],  
        TY.[name] AS system_data_type
FROM    test.sys.[tables] AS T  
    INNER JOIN test.sys.[all_columns] AC ON T.[object_id] = AC.[object_id] 
    INNER JOIN test.sys.[types] TY ON AC.[system_type_id] = TY.[system_type_id]

This will give you the list of Columns along with Table Name, Column Name and Data Type that is in master but not exists or different from test.

Answer 2

Have you done any searching?

http://www.codeproject.com/Articles/205011/SQL-Server-Database-Comparison-Tool