Given this specific line pulled from ifconfig
, in my case:
inet 192.168.2.13 netmask 0xffffff00 broadcast 192.168.2.255
How could one extract the 192.168.2.13
part (the local IP address), presumably with regex?
Here's one way using grep
:
line='inet 192.168.2.13 netmask 0xffffff00 broadcast 192.168.2.256'
echo "$line" | grep -oE "\b([0-9]{1,3}\.){3}[0-9]{1,3}\b"
Results:
192.168.2.13
192.168.2.256
If you wish to select only valid addresses, you can use:
line='inet 192.168.0.255 netmask 0xffffff00 broadcast 192.168.2.256'
echo "$line" | grep -oE "\b((25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\b"
Results:
192.168.0.255
Otherwise, just select the fields you want using awk
, for example:
line='inet 192.168.0.255 netmask 0xffffff00 broadcast 192.168.2.256'
echo "$line" | awk -v OFS="\n" '{ print $2, $NF }'
Results:
192.168.0.255
192.168.2.256
Addendum:
Word boundaries : \\b
使用这个正则表达式((25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\\.){3}(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)(?=\\s*netmask)
you can use egrep (which is basically the same as grep -E)
in egrep there are named groups for character classes, eg: "digit"
(which makes the command longer in this case - but you get the point...)
another thing that is good to know is that you can use brackets to repeat a pattern
ifconfig | egrep '([0-9]{1,3}\.){3}[0-9]{1,3}'
or
ifconfig | egrep '([[:digit:]]{1,3}\.){3}[[:digit:]]{1,3}'
if you only care about the actual IP address use the parameter -o to limit output to the matched pattern instead of the whole line:
ifconfig | egrep -o '([[:digit:]]{1,3}\.){3}[[:digit:]]{1,3}'
...and if you don't want BCast addresses and such you may use this grep:
ifconfig | egrep -o 'addr:([[:digit:]]{1,3}\.){3}[[:digit:]]{1,3}' | egrep -o '[[:digit:]].*'
I assumed you were talking about IPv4 addresses only
Just to add some alternative way:
ip addr | grep -Po '(?!(inet 127.\d.\d.1))(inet \K(\d{1,3}\.){3}\d{1,3})'
it will print out all the IPs but the localhost one.
[0-9]{1,3}\\.[0-9]{1,3}\\.[0-9]{1,3}\\.[0-9]{1,3}
I don't have enough reputation points to comment, but I found a bug in Steve's "select only valid addresses" regex. I don't quite understand the problem, but I believe I have found the fix. The first command demonstrates the bug; the second one demonstrates the fix:
$ echo "test this IP: 200.1.1.1" |grep -oE "\b(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?\.){3}(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\b"
$ echo "test this IP: 200.1.1.1" |grep -oE "\b((25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\b"
200.1.1.1
$
One way using sed
. First instruction deletes all characters until first digit in the line, and second instruction saves first IP in group 1 ( \\1
) and replaces all the line with it:
sed -e 's/^[^0-9]*//; s/\(\([0-9]\{1,3\}\.\)\{3\}[0-9]\{1,3\}\).*/\1/'
This code works nicely and easy too.
ifconfig | grep Bcast > /tmp/ip1
cat /tmp/ip1 | awk '{ print $2 }' > /tmp/ip2
sed -i 's/addr://' /tmp/ip2
IPADDRESS=$(cat /tmp/ip2)
echo "$IPADDRESS"
也许这个,一个sed命令,仅用于运动:
ip -o -4 addr show dev eth0 | sed 's/.* inet \([^/]*\).*/\1/'
grep -oE "\b([0-9]{1,3}\.?){4}\b"
This code works for me on raspberry pi zero w .
(extract wlan0: inet 192.168.xy address from ifconfig
output)
Search for pattern 'inet 192' in ifconfig output and get the 10th position using space delimiter.
$> ifconfig |grep 'inet 192'|cut -d' ' -f10
Output: 192.168.1.6
如果使用支持Perl正则表达式的grep:
(your command that pulls mentioned line) | grep -Po 'inet \K[\d\.]+'
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