C\C++: Initialize ASCII special char?

Question

How do you initialize special ASCII chars, for example EOT (0x04), ENQ(0x05)?

char CHAR1 = '\EOT';
char CHAR2 = '\ENQ';

Is this correct?

Answer 1

You can put character code into the variable:

char CHAR1 = 4;
char CHAR2 = 5;

You can also use escape sequences which you'll find here .

Answer 2

By hex or octal, there is no support for their names. '\\x04' eg.

Answer 3

You can simply assign char to its hexadecimal value:

char CHAR1 = 0x04;

Is this correct ? - no the way you initialize it is not correct as compiler expects one escape character after '\\'