I wonder if it is possible to have minimal code for this:
for (int x = 1; x < 10; x++){
/*I want to replace this condition with (x%number == 0)
instead of writing out condition for every number, but
it did not work with for (int number = 1; number <= 3; number++)
in (x%number == 0), as it prints out every x and number
*/
if ((x%1) == 0 && (x%2) == 0 & (x%3) == 0){
System.out.println(success!);
}
}
I think
x % a == 0 && x % b == 0 && x % c == 0
is equalent to
x % (a * b * c) == 0
UPDATE
Multiplication is incorrect, you need to use LCM : x % lcm(a, b, c)
Have a look :
for (int x = 1; x < 10; x++){
boolean flag = false;
for(int num = 1; num <= 3; num++){
if ((x%num) == 0 ){
flag = true;
}else{
flag = false;
break;
}
}
if(flag){
System.out.println(x + " success!");
}
}
OUTPUT :
6 success!
I know the code is looking a little horrified but will work for any value of x
and num
This is what you'd need to make a comp sci professor happy:
for (int x = 1; x < 10; x++){
boolean success = true;
for (int number = 1; number <= 3; number++) {
if ((x % number) != 0) {
success = false;
}
}
if (success) {
System.out.println("success!");
}
}
although note: (x % 1) is always 0.
This is what you'd need to make me happy, according to my rule of "avoid nested loops":
for (int x = 1; x < 10; x++) {
if (testNumber(x))
System.out.println(x + " success!");
}
}
private static boolean testNumber(int x) {
for (int number = 1; number <= 3; number++) {
if ((x % number) != 0) {
return false;
}
}
return true;
}
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