Java Find and Replace String using Regex
Question
I need to specify the string find in Regex format, in order that head tag can be found whatever its format is like <html > or <html> or < html> . How to specify the find string in Regex format?
String source = "<html >The quick brown fox jumps over the brown lazy dog.</html >";
String find = "<html>";
String replace = "";
Pattern pattern = Pattern.compile(find);
Matcher matcher = pattern.matcher(source);
String output = matcher.replaceAll(replace);
System.out.println("Source = " + source);
System.out.println("Output = " + output);
4 answers
solution1
3 2012-09-07 12:08:00
Although you could go round your problem by doing <\\\\s*html\\\\s*> , you should not process HTML with regex. Obligatory link .
The \\\\s* denotes 0 or more white spaces.
solution2
1 2012-09-07 12:11:22
Do not attempt to parse HTML using regex! Try reading about XPath . Very helpful. Although XPath will try by default to validate your document, but you can try HtmlCleaner to make it valid.
solution3
0 2012-09-07 12:09:36
To extract text inside your tags use something like
String source = "<html >The quick brown fox jumps over the brown lazy dog.</html >";
System.out.println( source.replaceAll( "^<\\s*html\\s*>(.*)<\\s*\\/html\\s*>$", "$1" ) );
// output is:
// The quick brown fox jumps over the brown lazy dog.
But try to avoid parsing of html by regexps. Read this topic .
solution4
0 2012-09-07 12:14:50
This example may be helpful to you.
String source = "<html >The quick brown fox jumps over the brown lazy dog.</html >";
String find = "\\<.*?>";
String replace = "";
Pattern pattern = Pattern.compile(find);
Matcher matcher = pattern.matcher(source);
String output = matcher.replaceAll(replace);
System.out.println("Source = " + source);
System.out.println("Output = " + output);
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