i am trying to delete certain portion of a string if a match found in the string as below
string = 'Newyork, NY'
I want to delete all the characters after the comma from the string including comma
, if comma is present in the string
Can anyone let me now how to do this .
Use .split()
:
string = string.split(',', 1)[0]
We split the string on the comma once , to save python the work of splitting on more commas.
Alternatively, you can use .partition()
:
string = string.partition(',')[0]
Demo:
>>> 'Newyork, NY'.split(',', 1)[0]
'Newyork'
>>> 'Newyork, NY'.partition(',')[0]
'Newyork'
.partition()
is the faster method:
>>> import timeit
>>> timeit.timeit("'one, two'.split(',', 1)[0]")
0.52929401397705078
>>> timeit.timeit("'one, two'.partition(',')[0]")
0.26499605178833008
You can split the string with the delimiter ","
:
string.split(",")[0]
Example:
'Newyork, NY'.split(",") # ['Newyork', ' NY']
'Newyork, NY'.split(",")[0] # 'Newyork'
Try this :
s = "this, is"
m = s.index(',')
l = s[:m]
A fwe options:
string[:string.index(",")]
This will raise a ValueError
if ,
cannot be found in the string. Here, we find the position of the character with .index
then use slicing.
string.split(",")[0]
The split
function will give you a list of the substrings that were separated by ,
, and you just take the first element of the list. This will work even if ,
is not present in the string (as there'd be nothing to split in that case, we'd have string.split(...) == [string]
)
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