C language. Declaration of the array, size of which is given by the macros #define

Question

I wonder why when I try to declare the array using #define I get errors from compiler, while using literal instead of the size allows me to do so.

some_name.h:

#define size 10;

int* waitingBench[size];

Answer 1

What you have will be pre-processed to:

int* waitingBench[10;];
//                  ^ notice this guy!

Remove the semicolon from the #define .

(And size is a really bad identifier to #define .)

Answer 2

Remove the ; from your definition. As you currently have it, this is equivillent to int* waitingBench[10;]; which you know is incorrect.

Macro definitions are not C instructions, so they do not need to be terminated with a semi-colon (and they must not exceed one line unless a line continuation backslash is used, and they must not share the line with something else).

Answer 3

Remove ";" in the end:

#define size 10