I have started working with the google Python class but I am getting some odd results and a full day of debugging hasn't help me resolve it.
What seems to be happening is that the functions are returning None instead of the values I am assigning them, but why this is happening is eluding me. I wrote in some debug lines and tried to step through it but I am seeing what is causing the behaviour.
Here is a sample of some of the debug output:
C:\Users\toshiba\Dropbox\DEV\python\google-python-exercises\basic>python string2.py
front_back
X got: None expected: 'abxcdy'
OK got: 'abcxydez' expected: 'abcxydez'
OK got: 'KitDontenut' expected: 'KitDontenut'
The code is from googles class and then the functions written by me.
# F. front_back
# Consider dividing a string into two halves.
# If the length is even, the front and back halves are the same length.
# If the length is odd, we'll say that the extra char goes in the front half.
# e.g. 'abcde', the front half is 'abc', the back half 'de'.
# Given 2 strings, a and b, return a string of the form
# a-front + b-front + a-back + b-back
def front_back(a, b):
# +++your code here+++
# Debug hardcode setting
# set to 1 to debug (default 0 off)
letsDebug = 0
alpha, bravo = a, b
if letsDebug == 1:
endString = a \
+ ' ' \
+ b
return endString
lenA = len(alpha)
lenB = len(bravo)
if lenA % 2 == 1:
statAlpha = 'odd'
else:
statAlpha = 'even'
if lenB % 2 == 1:
statBravo = 'odd'
else:
statBravo = 'even'
if letsDebug == 2:
endString = a \
+ ' ' \
+ b \
+ ' ' \
+ statAlpha \
+ ' ' \
+ statBravo
return endString
workB = lenB / 2
workA = lenA / 2
if letsDebug == 3:
endString = a \
+ ' ' \
+ b \
+ ' ' \
+ statAlpha \
+ ' ' \
+ statBravo \
+ ' ' \
+ str(workA) \
+ ' ' \
+ str(workB)
return endString
if statAlpha == 'even':
aFront, aBack = alpha[:workA], alpha[-workA:]
else:
aFront, aBack = alpha[:(workA+1)], alpha[-workA:]
if statBravo == 'even':
bFront, bBack = bravo[:workB], bravo[-workB:]
else:
bFront, bBack = bravo[:(workB+1)], bravo[-workB:]
if letsDebug == 4:
endString = a \
+ ' ' \
+ str(workA) \
+ ' ' \
+ b \
+ ' ' \
+ str(workB) \
+ ' ' \
+ statAlpha \
+ ' ' \
+ statBravo \
+ ' ' \
+ aFront \
+ ' ' \
+ bFront \
+ ' ' \
+ aBack \
+ ' ' \
+ bBack \
+ ' ' \
+ aFront + bFront + aBack + bBack
else:
endString = aFront + bFront + aBack + bBack
return endString
# Simple provided test() function used in main() to print
# what each function returns vs. what it's supposed to return.
def test(got, expected):
if got == expected:
prefix = ' OK '
else:
prefix = ' X '
print '%s got: %s expected: %s' % (prefix, repr(got), repr(expected))
# main() calls the above functions with interesting inputs,
# using the above test() to check if the result is correct or not.
def main():
print 'verbing'
test(verbing('hail'), 'hailing')
test(verbing('swiming'), 'swimingly')
test(verbing('do'), 'do')
print
print 'not_bad'
test(not_bad('This movie is not so bad'), 'This movie is good')
test(not_bad('This dinner is not that bad!'), 'This dinner is good!')
test(not_bad('This tea is not hot'), 'This tea is not hot')
test(not_bad("It's bad yet not"), "It's bad yet not")
print
print 'front_back'
test(front_back('abcd', 'xy'), 'abxcdy')
test(front_back('abcde', 'xyz'), 'abcxydez')
test(front_back('Kitten', 'Donut'), 'KitDontenut')
if __name__ == '__main__':
main()
Many thanks to any who can decipher where I have gone ary here.
You have a path out of the last if in front_back() that is not covered by a return statement. This one:
if statBravo == 'even':
It looks like the whole block at the end of front_back
is indented one too many levels. From if letsDebug == 4:
to return endString
- this is all part of the else block started above it (the else
for the statement if statBravo == 'even':
). I'm guessing this is supposed to be at function scope instead.
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