Extract number from a string

Question

I need to get all numbers from a string like this:

"156234   something 567345 another thing 45789 anything"

The result should be a collection of numbers having:

156234, 567345, 45789

I tried @"\\d+" , but it will only give me 156234 .

EDIT: The numbers are integers, however they can also occur like this "156234 something 567345 another thing 45789 anything2345". In this case I only need the integers ie 156234, 567345, 45789 and not 156234, 567345, 45789,2345.

Also the integers which i dont want will always be preceed with a text for ex:anything2345.

Answer 1

Everything is ok with your regex, you just need to come through all the matches.

Regex regex = new Regex(@"\d+");

foreach (Match match in regex.Matches("156234 something 567345 another thing 45789 anything"))
{
    Console.WriteLine(match.Value);
}

Answer 2

You want to split on the characters, not the digits. Use the capital D

string[] myStrings = Regex.Split(sentence, @"\D+");

Source

Answer 3

If 2345 should not be matched in your revised sample string (156234 something 567345 another thing 45789 anything2345), you could use Dima's solution but with the regex:

\b\d+\b

This assures that the number is surrounded by word boundaries.

Answer 4

This'z in java. You don't actually need a Regex.. just a normal replaceAll should do the trick for you! : For ex : You can strip off the Non-Digits, and then split and calculate the sum.

  public static int getSumOfNumbers(String s) {
    int sum = 0;
    String x = s.replaceAll("\\D+", " ");
    String[] a = x.split(" ");
    for(int i = 0; i < a.length; i++)
         sum += Integer.parseInt(a[i]);
    System.out.println(x + " : and sum is : "+sum);
    return sum;
}