I want to symbolically link two arrays' elements. For example, array1 = (AAA BBB CCC DDD)
, array2 = (001 002 003 004)
, 001->AAA
, 002->BBB
, 003->CCC
and 004->DDD
.
Here is the shell script I wrote, but it doesn't work, and I couldn't figure out where is wrong.
declare -a array1=(AAA BBB CCC DDD)
declare -a array2=(001 002 003 004)
num = ${#array1[@]}
ssh username@hostmachine 'for((i = 0 ; i < $num ; i++ )); do ln -sf ${array1[$i]} ${array2[$i]}; done'
Can anyone give me some hints/advice? Thank you in advance.
You should include all your bash code inside the parameter to ssh
, like this:
ssh username@hostmachine 'declare -a array1=(AAA BBB CCC DDD); declare -a array2=(001 002 003 004); num = ${#array1[@]}; for((i = 0 ; i < $num ; i++ )); do ln -sf ${array1[$i]} ${array2[$i]}; done'
because otherwise the ssh bash code won't get access to your previously defined arrays, because they were defined in your computer not in the ssh one.
初看起来,我会说你错过了循环中的最后done
:
ssh username@hostmachine 'for((i = 0 ; i < $num ; i++ )); do ln -sf ${array1[$i]} ${array2[$i]}; done'
The variable substitution isn't happening insside single quotes. Try double quotes instead:
declare -a array1=(AAA BBB CCC DDD)
declare -a array2=(001 002 003 004)
num=${#array1[@]}
ssh username@hostmachine "for((i = 0 ; i < $num ; i++ )); do ln -sf ${array1[$i]} ${array2[$i]}; done"
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