I have a small table that looks like this:
PLAN YRMTH
A2BKG 197001
A2BKG 200205
A2BKG 200308
A2BKG 200806
From this table, how do I get a table such as the one below?
PLAN STARTDATE ENDDATE
A2BKG 197001 200205
A2BKG 200205 200308
A2BKG 200308 200806
A2BKG 200806 NULL
Try this
;with cte as
(select *, ROW_NUMBER() over (partition by [plan] order by yrmth) rn from yourtable)
select
t1.[plan],
t1.YRMTH as startdate,
t2.YRMTH as enddate
from cte t1
left join cte t2 on t1.[plan]=t2.[plan]
and t1.rn=t2.rn-1
这是我在oracle中尝试过的同样可用于sql-server 2012以及....我的坏:(
select plan,yrmth,lead(yrmth) over (partition by lower(plan) order by rowid) from tbl;
Something like this could help:
SELECT
[PLAN],
YRMTH AS STARTDATE,
(SELECT MIN(YRMTH) FROM yourTable T
WHERE T.[Plan] = yourTable.[Plan] AND T.YRMTH > Test1.YRMTH) AS ENDDATE
FROM yourTable
select t1.PLAN, t2.STARTDATE,
(select top 1 STARTDATE from table t2 where t1.PLAN =t2.PLAN
and t1.STARTDATE<t2.STARTDATE) as ENDDATE
from table t1
Temp table solution from me.
-- Create a temp table, containing an extra column, ID
DECLARE @orderedPlans
(
ID int,
Plan varchar(64),
YrMth int
)
-- Use contents of your table, plus ROW_NUMBER, to populate
-- temp table. ID is sorted on Plan and YrMth.
--
INSERT INTO
@orderedPlans
(
ID,
Plan,
YrMth
)
SELECT ROW_NUMBER() OVER (ORDER BY Plan, YrMth) AS ID,
Plan,
YrMth
FROM
YourTable
-- Now join your temp table on itself
-- Because of the ROW_NUMBER(), we can use ID - 1 as a join
-- Also join on Plan, so that the query can handle multiple plans being
-- in the table
SELECT
p1.Plan,
p1.YrMth AS StartDate,
p2.YrMth AS EndDate
FROM
@orderedPlans p1
LEFT JOIN
@orderedPlans p2
ON
p1.Plan = p2.Plan
AND p1.ID = p2.ID - 1
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