I have a string :
$str = " Côte-d'azure ! (3000) limousin - limousine ";
And I need to extract some words and put them in an array. to get finally :
array (
0 => "Côte-d'azure",
1 => "limousin",
2 => "limousine"
);
So I tried :
preg_match_all("/[a-zA-Z]+/", $str, $all);
but this ignore the special character ô , ' and -
please any advise ?
Use Unicode mode u
and character properties :
preg_match_all('/\p{L}[\p{L}\\\\\'-]+/u', mysql_real_escape_string($str), $all);
This requires one (Unicode) letter and then matches as many other Unicode letters, backslashes, hyphens and apostrophes as possible. If you want other punctuation characters to not separate a word, include it in the character class.
Note that 5 backslashes. Three backslashes are removed when the string is compiled, because two of them escape the backslash following them, and the last one escapes the '
. So the regex engine receives only 2 backslashes. These are interpreted by the regex engine as one literal backslash. Unfortunately there is no way to use less than 4 backslashes to represent one literal backslash when using PHP.
try
if (preg_match('/[^a-zA-Z0-9]+/', $your_string, $matches))
{
echo ' symbol encountered !!';
}
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