I want to know if I could, pass in a pointer of an instance of a class, get it's member functions and store it in a list. How would I do that?
Easy way is with some template magic and inheritance:
template<class R>
class Base {
public:
virtual R Execute() const=0;
};
template<class R, class P1, class P2>
class Derived : public Base<R> {
public:
void set_params(P1 p1, P2 p2) { m_p1 = p1; m_p2 = p2; }
R Execute() const { return Map(m_p1,m_p2); }
protected:
virtual R Map(P1, P2) const=0;
private:
P1 m_p1;
P2 m_p2;
};
template<class T, class R, class P1, class P2>
class MemFunc : public Derived<R,P1,P2> {
public:
MemFunc(T *object, R (T::*fptr)(P1, P2)) : object(object), fptr(fptr) { }
virtual R Map(P1 p1, P2 p2) const { return (object->*fptr)(p1,p2); }
private:
T *object;
R (T::*fptr)(P1,P2);
};
And then main() function would look like:
int main() {
std::vector<Base<int>*> vec;
Object o;
Derived<int, float,float> *ptr = new MemFunc(&o, &Object::MyFunc);
ptr->set_params(10.0,20.0);
vec.push_back(ptr);
int i = vec[0].Execute();
}
Once you want all member functions of a class stored, you need several vectors:
std::vector<Base<int>*> vec_int;
std::vector<Base<float>*> vec_float;
std::vector<Base<MyObject>*> vec_myobject;
Long answer, here is a tutorial for function pointers in C++ tutorial page
Short answer, here is a example of storing a function pointer in an array. Note not compiled.
typedef void(*pFunc)(void); //pFunc is an alias for the function pointer type
void foo1(){};
void foo2(){}
int main(){
pFunc funcs[2] = {&foo1, &foo2}; //hold an array of functions
}
Now member function is a little different syntax:
struct Foo{
void foo1(){}
void foo2(){}
}
typedef (*Foo::pFunc)(); //pFunc is an alias to member function pointer
int main(){
pFunc funcs[2] = {&Foo::foo1, &Foo::foo2};
}
Your best bet is to check out the link I placed here. It delves into the sytax and more. If you are using the new C++11, then you may utilize std::function, or if you have boost, you can use boost::function.
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