Regex in java for alphanumeric

Question

I have one string like 010000200000, 000000200000, 020000200000 . I want to create regex for this and want to check that first 2 digit will be only 01,00 & 02. And rest of the digit should be only from [0-6].

I don't want any space or any special character in this string. I try some of the regex available online but didn't help me exactly.

If anyone has any idea please kindly help.

Answer 1

This should parse them with your requirements.

java.util.regex.Pattern.matches("0[012][0-6]+", "010000200000");

The first character is always a 0, followed by 1 character that is a 0, 1 or 2, followed by at least 1 character in the 0-6 range.

Answer 2

Straightforward

"0[012][0-6]*"

Start with 0, next a 0, 1 or 2, and than any amount of digits between 0 and 6.

Answer 3

I recommend you have a look at this tutorial .

If the number of digits and number of segments of your string is fixed, you could use

(?:0[012][0-6]{10}, ){2}0[012][0-6]{10}

If they are not, simply

(?:0[012][0-6]*, )*0[012][0-6]*

If you actually meant the given example is three separate strings, then it's even easier:

0[012][0-6]{10}

or

0[012][0-6]*

All this uses is character classes and repetition .

Note that these will only behave as you like when you use them with Pattern.matches . If not, surround them with ^...$ to make sure there is nothing else in front of or after this pattern.

Answer 4

java.util.regex.Pattern.matches("0[0-2]{1}[3-6]{10}", "015453356543")    

这正是正则表达式所需要的...是吗？

Answer 5

What about 0[0-2][0-6][0-6][0-6][0-6][0-6][0-6][0-6][0-6][0-6][0-6] ? Obviously I guessed you need a fixed length string of 12 chars, otherwise 0[0-2][0-6]+ would be ok.