Here is my code:
$query1 = "select user, sum(column) as total1 from table1 GROUP BY user";
$result = mysql_query(query1);
$row_query1 = mysql_fech_assoc($result);
do{
$user = $row_query1['user'];
$query2 = "select names, sum(column1) as total2 from table2 WHERE names ='$user' GROUP BY names";
$result2 = mysql_query($query2);
$row_query2 = mysql_fetch_assoc($result2);
$sum = $row_query1['total1'] + $row_query2['total1'];
<tr> <?php echo $sum; ?></tr>
}while($row_query1 = mysql_fech_assoc($result));
I need to get the highest value of $sum from this loop. Can anyone help?
You can do like this.. take a temporary variable($temp) which can have check upon the sum variable($sum).
$query1 = "select user, sum(column) as total1 from table1 GROUP BY user";
$result = mysql_query(query1);
$row_query1 = mysql_fech_assoc($result);
$temp = 0;
do{
$user = $row_query1['user'];
$query2 = "select names, sum(column1) as total2 from table2 WHERE names ='$user' GROUP BY names";
$result2 = mysql_query($query2);
$row_query2 = mysql_fetch_assoc($result2);
$sum = $row_query1['total1'] + $row_query2['total1'];
if($temp < $sum)
$temp = sum;
echo "<tr>$sum</tr>";
}while($row_query1 = mysql_fech_assoc($result));
echo "maximum sum :".$temp;
I would advice doing a JOIN instead of performing the sub queries yourself:
select user, sum(column) + sum(column1) as total
from table1
INNER JOIN table2 ON names = user
GROUP BY user
The rest should be straightforward in code.
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.