multiprocessing.manager issue sys.args

Question

I am running the following python line of code within a small windows service application which is multiprocessed.

multiprocessing.Manager()

The issue is there appears to be no attribute argv within the module sys set when running a windows service. As a result of this I get the following error occur within the python multiprocessing forking library. I was hoping someone might be able to shed some light on this issue.

Stacktrace of issue (when running multiprocessing.Manager within windows service):

 File "C:\python27\lib\multiprocessing\__init__.py", line 99, in Manager
    m.start()
  File "C:\python27\lib\multiprocessing\managers.py", line 524, in start
    self._process.start()
  File "C:\python27\lib\multiprocessing\process.py", line 130, in start
    self._popen = Popen(self)
  File "C:\python27\lib\multiprocessing\forking.py", line 252, in __init__
    cmd = get_command_line() + [rhandle]
  File "C:\python27\lib\multiprocessing\forking.py", line 339, in get_command_line
    if process.current_process()._identity==() and is_forking(sys.argv):
AttributeError: 'module' object has no attribute 'argv

Update

One possible solution to my problem is that I manually set the sys.argv value if it is not set at runtime but this seems very unpythonic. But might be the only solution. What do stackoverflow-ers think?

if not hastattr(sys, 'argv'):
    sys.argv = []

But, this then leads me to a new issue with the multiprocessing.manager where by an unexpected EOFError occurs within the code.

  File "C:\python27\lib\multiprocessing\__init__.py", line 99, in Manager
    m.start()
  File "C:\python27\lib\multiprocessing\managers.py", line 528, in start
    self._address = reader.recv()
  EOFError

Answer 1

Since setting sys.argv = [] didn't work, if there is a script name you might be able to use do sys.argv = ['scriptname'] or just sys.argv = [''] . The latter is what you get if you run python, import sys and then look at sys.argv , eg,

~$ python
>>> import sys
>>> sys.argv
['']

Answer 2

Call this function after Python initialization:

PySys_SetArgv(argc, argv);

The interpreter can't get access to argc/argv in other way rather then passing them explicitly from main().