So I know you can't cast from base type to derived type because an Animal might not be a Cat etc etc.
Given that, can you suggest a better way to implement this code, and avoid having to repeat the operator declaration and instantiate new objects?
class scientific_number
{
public decimal value;
public int precision;
public static implicit operator scientific_number(decimal value)
{
return new scientific_number() { value = value, precision = 0 };
}
public static implicit operator scientific_number(int value)
{
return new scientific_number() { value = (decimal)value, precision = 0 };
}
public static implicit operator scientific_number(double value)
{
return new scientific_number() { value = (decimal)value, precision = 0 };
}
}
class amu : scientific_number
{
public static implicit operator amu(scientific_number scientific_number)
{
return new amu() { value = scientific_number.value, precision = scientific_number.precision };
}
public static implicit operator amu(decimal value)
{
return new amu() { value = value, precision = 0 };
}
public static implicit operator amu(int value)
{
return new amu() { value = (decimal)value, precision = 0 };
}
public static implicit operator amu(double value)
{
return new amu() { value = (decimal)value, precision = 0 };
}
public kg ToEarthKg()
{
return this.value / 0.00000000000000000000000000166053886;
}
}
class kg : scientific_number
{
public static implicit operator kg(scientific_number scientific_number)
{
return new kg() { value = scientific_number.value, precision = scientific_number.precision };
}
public static implicit operator kg(decimal value)
{
return new kg() { value = value, precision = 0 };
}
public static implicit operator kg(int value)
{
return new kg() { value = (decimal)value, precision = 0 };
}
public static implicit operator kg(double value)
{
return new kg() { value = (decimal)value, precision = 0 };
}
}
So I know you can't cast from base type to derived type because an Animal might not be a Cat etc etc.
Wrong.
You can, if the object is not of the target type you'll get an exception.
If you use the as
operator and the target type is a reference type you'll get null if the cast cannot be performed.
So
Animal d = new Dog();
var c = (Cat)d; // Will throw
var c1 = d as Cat; // Will return null (assuming Dog is a reference type).
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