Replace specific char in char *

Question

I want to replace a certain char with a newline. Here is my code:

char *string = ReadResource(); //returns pointer to array using memcpy()
char *FinalString = string;   
for(int x=0; x< int(SizeOfRes); x++)
      {
          if (string[x] == char(84)) 
            FinalString[x] = HERE DO I WANT A NEWLINE;

          else 
            FinalString[x] = string[x];
      }

I know that char * is read-only since this is a pointer to an array stored in the memory so using FinalString[x] = '\\n'; doesn't work.

But I can't strcpy() the array either because it contains NULL bytes.

Is there a simple way to achieve this?

Answer 1

Use memcpy() if your array contains NULL characters.

A basic program which works :

#include <iostream>
#include <fstream>
#include <cstring>
using namespace std;

int main(int argc, char *argv[])
{
  char *cbuffer = "hello \x00world";
  char buffer[12];
  memcpy((void *)buffer, (void *)cbuffer, 12);
  buffer[2] = 'h';  
  ofstream ofs ("nullfile.bin", ios::binary);
  ofs.write(buffer,12);
  return 0;
}