加快Python 2.7中的功能

Question

我想知道，是否有一种方法可以加快此处显示的功能。 我知道这看起来不太pythonic ...

def MakePairs(inputlist):
   '''
    @param inputlist: [[["a","b","c"],["d","e","f"]],[["g","h","i"],["j","k","l"]],...]
    @return returnlist: [[["a","d"],["b","e],["c","f"]],[["g","j"],["h","k"],["i","l"]],...]
    '''
    returnlist = []
    for Pair in xrange(len(inputlist)):
        dummy2 = []
        for item in xrange(len(inputlist[Pair][0])):
            dummy = [Pair[0][item], Pair[1][item]]
            dummy2.append(dummy)
        returnlist.append(dummy2)

    return returnlist

编辑：返回列表中的对必须是列表。

提前致谢！！！

Answer 1

看起来像zip() ：

>>> l = [[["a","b","c"],["d","e","f"]],[["g","h","i"],["j","k","l"]]]
>>> [zip(*item) for item in l]
[[('a', 'd'), ('b', 'e'), ('c', 'f')], [('g', 'j'), ('h', 'k'), ('i', 'l')]]

因此，您的功能将是：

def MakePairs(inputlist):
    return [zip(*item) for item in inputlist]

另外，考虑使用itertools.izip（）而不是zip（）。