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[英]Issue with converting a pandas column from int64 to datetime64
[英]Converting column from int64 to datetime in hdf5 file using Python's Pandas package
我是熊猫和编程的新手,所以对您的帮助将不胜感激。
我很难将从hdf5文件加载的Pandas数据框中的数据列转换为datetime对象。 数据太大,无法使用文本文件,因此我使用以下代码将其转换为hdf5文件:
# get text file from zip file and unzip
file = urllib.request.urlretrieve(file, dir)
z = zipfile.ZipFile(dir)
data = z.open(z.namelist()[0])
# column names from text file
colnames = ['Patent#','App#','Small','Filing Date','Issue Date', 'Event Date', 'Event Code']
# load the data in chunks and concat into single DataFrame
mfees = pd.read_table(data, index_col=0, sep='\s+', header = None, names = colnames, chunksize=1000, iterator=True)
df = pd.concat([chunk for chunk in mfees], ignore_index=False)
# close files
z.close()
data.close()
# convert to hdf5 file
data = data.to_hdf('mfees.h5','raw_data',format='table')
之后,我的数据采用以下格式:
data['Filing Date']
输出:
Patent#
4287053 19801222
4287053 19801222
4289713 19810105
4289713 19810105
4289713 19810105
4289713 19810105
4289713 19810105
4289713 19810105
Name: Filing Date, Length: 11887679, dtype: int64
但是,当我使用to_datetime函数时,得到以下信息:
data['Filing Date'] = pd.to_datetime(data['Filing Date'])
data['Filing Date']
输出:
Patent#
4287053 1970-01-01 00:00:00.019801222
4287053 1970-01-01 00:00:00.019801222
4289713 1970-01-01 00:00:00.019810105
4289713 1970-01-01 00:00:00.019810105
4289713 1970-01-01 00:00:00.019810105
4289713 1970-01-01 00:00:00.019810105
4289713 1970-01-01 00:00:00.019810105
4289713 1970-01-01 00:00:00.019810105
4289713 1970-01-01 00:00:00.019810105
4291808 1970-01-01 00:00:00.019801212
4291808 1970-01-01 00:00:00.019801212
4292069 1970-01-01 00:00:00.019810123
4292069 1970-01-01 00:00:00.019810123
4292069 1970-01-01 00:00:00.019810123
4292069 1970-01-01 00:00:00.019810123
Name: Filing Date, Length: 11887679, dtype: datetime64[ns]
我不确定为什么我得到上述datetime对象的输出。 有什么我可以纠正的方法并将日期正确转换为datetime对象吗? 谢谢!
读parse_dates=[1]
最容易转换(请注意,我复制了粘贴的数据,因此您只需要添加parse_dates=[1]
选项
In [31]: df = read_csv(StringIO(data),sep='\s+',header=None,parse_dates=[1],names=['num','date']).set_index('num')
In [32]: df
Out[32]:
date
num
4287053 1980-12-22 00:00:00
4287053 1980-12-22 00:00:00
4289713 1981-01-05 00:00:00
4289713 1981-01-05 00:00:00
4289713 1981-01-05 00:00:00
4289713 1981-01-05 00:00:00
4289713 1981-01-05 00:00:00
4289713 1981-01-05 00:00:00
In [33]: df.dtypes
Out[33]:
date datetime64[ns]
dtype: object
然后hdf将处理列
In [46]: df.to_hdf('test.h5','df',mode='w',format='table')
In [47]: pd.read_hdf('test.h5','df')
Out[47]:
date
num
4287053 1980-12-22 00:00:00
4287053 1980-12-22 00:00:00
4289713 1981-01-05 00:00:00
4289713 1981-01-05 00:00:00
4289713 1981-01-05 00:00:00
4289713 1981-01-05 00:00:00
4289713 1981-01-05 00:00:00
4289713 1981-01-05 00:00:00
In [48]: pd.read_hdf('test.h5','df').dtypes
Out[48]:
date datetime64[ns]
dtype: object
这是一个类似int的日期的转换器,应该很快
In [18]: s = Series([19801222,19801222] + [19810105]*5)
In [19]: s
Out[19]:
0 19801222
1 19801222
2 19810105
3 19810105
4 19810105
5 19810105
6 19810105
dtype: int64
In [20]: s = s.values.astype(object)
In [21]: Series(pd.lib.try_parse_year_month_day(s/10000,s/100 % 100, s % 100))
Out[21]:
0 1980-12-22 00:00:00
1 1980-12-22 00:00:00
2 1981-01-05 00:00:00
3 1981-01-05 00:00:00
4 1981-01-05 00:00:00
5 1981-01-05 00:00:00
6 1981-01-05 00:00:00
dtype: datetime64[ns]
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