![](/img/trans.png)
[英]finding minimum and maximum element value from XML attributes using python
[英]Finding the Maximum and Minimum value in python using loops
我有一个分配,让用户输入尽可能多的分数,然后我必须计算最小和最大值,以及有多少人使用for循环获得这些分数。 我已经计算出平均值和标准偏差:
elif user_option == 3:
total = 0
for val in scores_list:
total = total + val
average = total/ len(scores_list)
print (average)
elif user_option == 2:
total = 0
for val in scores_list:
total = total + val
average = total/ len(scores_list)
diffsquared = 0
sum_diffsquared = 0
for val in scores_list:
diffsquared= (val - average)**2
sum_diffsquared= diffsquared + sum_diffsquared
stdev= sqrt((sum_diffsquared)/len(scores_list))
print(stdev)
任何想法如何找到最小值和最大值?
像这样吗
min_val = float("inf")
max_val = -float("inf")
count_min = 0
count_max = 0
for val in scores_list:
if val < min_val:
min_val = val
count_min = 1
elif val == min_val:
count_min += 1
if val > max_val:
max_val = val
count_max = 1
elif val == max_val:
count_max += 1
print "Minimum score:", min_val
print "Maximum score:", max_val
print "Number of students with minimum score:", count_min
print "Number of students with maximum score:", count_max
编辑:正如@ GL770在注释中指出的那样,sys.maxint仅在Python 2.x中可用。 在Python 2.x中,您可以完成以下操作:
import sys
min_val = sys.maxint
max_val = -sys.maxint - 1
尽管float("inf")
东西也可以在Python 2.x中使用,所以不需要此方法。
内置函数min()和max()怎么样:
scores_min = min(scores_list)
scores_max = max(scores_list)
也不要忘记numpy:
import numpy
scores_array = numpy.array(scores_list)
scores_mean = numpy.mean(scores_array)
scores_std = numpy.std(scores_array)
scores_min = numpy.min(scores_array)
scores_max = numpy.max(scores_array)
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.