[英]2d arrays and how to populate them with one dimensional arrays
这是我的代码:
def SetUpScores():
scoreBoard= []
names = ["George", "Paul", "John", "Ringo", "Bryan"]
userScores = [17, 19, 23, 25, 35]
for i in range(0,5):
scoreBoard.append([])
for j in range(0,2):
scoreBoard[i].append(names[i])
scoreBoard[i][1]= userScores[i]
我基本上是在尝试创建一个包含名称和userScore的二维数组,我对此进行了很多查找,到目前为止,我一直在使列表分配索引的错误超出范围,或者无法调用“列表”。
如果我从代码中删除最后一行,即:
def SetUpScores():
scoreBoard= []
names = ["George", "Paul", "John", "Ringo", "Bryan"]
userScores = [17, 19, 23, 25, 35]
for i in range(0,5):
scoreBoard.append([])
for j in range(0,2):
scoreBoard[i].append(names[i])
我懂了
[['George','George'],['Paul','Paul'],['John','John'],['Ringo','Ringo'],['Bryan','Bryan'] ]而没有任何错误(这只是为了测试是否制作了数组)。
我想做些类似的事情:
[['George',17],['Paul',19],['John',23],['Ringo',25],['Bryan',35]]
任何帮助,将不胜感激,谢谢!
使用scoreBoard[i].append(names[i])
,您可以添加单个元素,而不是列表。 因此,下一行scoreBoard[i][1]= userScores[i]
会导致错误,因为它引用了names[i]
的第二个元素,它只是一个字符串。
做您想做的最紧凑的方法是
for name, score in zip(names, userScores):
scoreBoard.append([name, score])
names = ["George", "Paul", "John", "Ringo", "Bryan"]
userScores = [17, 19, 23, 25, 35]
L3 =[]
for i in range(0, len(L1)):
L3.append([L1[i], L2[i]])
print(L3)
Output:
[[17, 'George'], [19, 'Paul'], [23, 'John'], [25, 'Ringo'], [35, 'Bryan']]
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.