我正在尝试调试给定的python代码，但给出了给定的错误

Question

我收到错误信息

Traceback:
    in <module>
    in merge_ranges
    TypeError: 'int' object is not iterable

有人可以建议出什么问题吗，也可以用于调试吗？

meets = [(1,3),(5,8),(8,14),(13,17)]
print '{} should be {}'.format(merge_ranges(meets))

def merge_ranges(meets):

    #sort by start time
    sorted_meetings = sorted(meets)

    merged_meetings = sorted_meetings[0]

    for current_meeting_start, current_meeting_end in sorted_meetings[1:]:
        last_merged_meeting_start, last_merged_meeting_end = merged_meetings[-1]

        if (current_meeting_start <= last_merged_meeting_end):
            merged_meetings[-1] = (last_merged_meeting_start, max(last_merged_meeting_end, current_meeting_end))

        else:
            merged_meetings.append((current_meeting_start, current_meeting_end))
    # write the body of your function here
    return merged_meetings

Answer 1

您merged_meetings变量merged_meetings初始化为单个元组，但是它应该是元组列表。

因此，您必须将merged_meetings的初始化修改为

merged_meetings = [sorted_meetings[0]]

测试用例的结果将是

[(1, 3), (5, 17)]

Answer 2

您不能像下面两行那样更改元组：

merged_meetings[-1] = (last_merged_meeting_start, max(last_merged_meeting_end, current_meeting_end)) # here

merged_meetings.append((current_meeting_start, current_meeting_end)) # and here

元组是不可变的。 您不仅在使用元组，而且还释放了超出应有的值。

Answer 3

问题在这一行：

last_merged_meeting_start, last_merged_meeting_end = merged_meetings[-1]

merged_meetings是一个元组，例如(1,3) 。
merged_meetings[-1]是单个值3。

您尝试将3解压缩为两个变量，这是不可能的。