如何替换列表特定元素的某些部分？

Question

您将如何替换列表中某些项目的一部分？ (Python 3.x) 假设我有一个列表：

x = ["part2keep removeMe", "saveme removeMe", "third length to throw it off removeMe", "element to save", "KeepThisPart"]

如果我只想删除“removeMe”部分，你会怎么做？ 到目前为止我有这个：

def replaceExampleA(x, y):
    for i in x:
        if i[len(i)-8:len(i)-1] == "removeMe":
            y.append(i[0: -12])
        else:
            y.append(i)

编辑：刚刚意识到我犯了一个错误 - 列表更像是这样的： x = ["part2keep removeMe 123", "saveme removeMe 12", "third length to throw it off removeMe 83", "element to save", "KeepThisPart"]

我还需要使用“removeMe”从元素中删除数字。 谢谢

Answer 1

x = [s.replace('removeMe', '') for s in x]

Answer 2

这可以通过列表理解来完成

x = ["part2keep removeMe", "saveme removeMe", "third length to throw it off removeMe"]

print(y.replace(' removeMe', '') for y in x)

Answer 3

您可以使用正则表达式来确保代码始终仅在出现在字符串末尾时才剥离removeMe ：

import re
x = ["part2keep removeMe", "saveme removeMe", "third length to throw it off removeMe", "element to save", "KeepThisPart"]
new_x = [re.sub('\sremoveMe$', '', i) for i in x]

输出：

['part2keep', 'saveme', 'third length to throw it off', 'element to save', 'KeepThisPart']

Answer 4

您还可以使用map功能

new_x = map(lambda e: e.replace('removeMe', ''), x)

这样做的好处是你可以拿回发电机。 因此，在某些情况下，这会提高内存效率。 如果你想要一个列表，就像其他答案一样，那么你需要将它转换回一个列表

new_x = list(new_x)