使用Pandas将suds对象转换为数据框

Question

我有一个看起来像这样的列表：

`[(deliveryObject){
   id = "0bf003ee0000000000000000000002a11cb6"
   start = 2019-01-02 09:30:00
   messageId = "68027b94b892396ed29581cde9ad07ff"
   status = "sent"
   type = "normal"
   }, (deliveryObject){
   id = "0bf0BE3ABFFDF8744952893782139E82793B"
   start = 2018-12-29 23:00:00
   messageId = "0bc403eb0000000000000000000000113404"
   status = "sent"
   type = "transactional"
 }, (deliveryObject){
   id = "0bf0702D03CB42D848CBB0B0AF023A87FA65"
   start = 2018-12-29 23:00:00
   messageId = "0bc403eb0000000000000000000000113403"
   status = "sent"
   type = "transactional"
   }
]`

当我调用type() Python告诉我这是一个列表。

当我使用pd.DataFrame(df)将其转换为数据pd.DataFrame(df) ，结果如下所示：

有人能帮我一下吗？ 该数据框应该具有列名，例如“ Id”，“ Start”，“ messageId”等，但它们只是作为每个观察值的第一个元素出现，而列名则显示为0、1、2等。

任何帮助表示赞赏，谢谢！

Answer 1

好的，这看起来不漂亮，但可以。 我将您的列表转换为字符串：

import re
import pandas as pd

x = """[(deliveryObject){
   id = "0bf003ee0000000000000000000002a11cb6"
   start = 2019-01-02 09:30:00
   messageId = "68027b94b892396ed29581cde9ad07ff"
   status = "sent"
   type = "normal"
   }, (deliveryObject){
   id = "0bf0BE3ABFFDF8744952893782139E82793B"
   start = 2018-12-29 23:00:00
   messageId = "0bc403eb0000000000000000000000113404"
   status = "sent"
   type = "transactional"
 }, (deliveryObject){
   id = "0bf0702D03CB42D848CBB0B0AF023A87FA65"
   start = 2018-12-29 23:00:00
   messageId = "0bc403eb0000000000000000000000113403"
   status = "sent"
   type = "transactional"
   }
]"""

然后，我使用正则表达式以某种方式列出字典：

a = re.sub(' =', ':', x)
a = re.sub('\(deliveryObject\)', '', a)

for x in ['id', 'start', 'messageId', 'status', 'type']:
    a = re.sub(x, '\''+x+'\'', a)

a = re.sub("(?<=[\"0])\n(?= +?[\'])", '\n,', a)
a = re.sub('(?<=[0])\n(?=,)', '\"\n', a)
a = re.sub('(?<=[:]) (?=[0-9])', ' \"', a)
a = re.sub('(?<= )\"(?=[\w])', '[\"', a)
a = re.sub('(?<=[\w])\"(?=\n)', '\"]', a)

现在，您有了字典列表。 第一排看起来像这样

list_of_dict = eval(a)
df = pd.DataFrame(list_of_dict[0])
print(df.head())

                                     id                start                         messageId status    type
0  0bf003ee0000000000000000000002a11cb6  2019-01-02 09:30:00  68027b94b892396ed29581cde9ad07ff   sent  normal

从list_of_dict添加其余的字典。

请随意改善我的正则表达式，我知道它看起来很糟糕。

Answer 2

如果这是针对bronto的，并且正在使用SOAP和suds实现。 然后，deliveryObject只是一个suds对象。

你可以做

from suds.client import Client

list_of_deliveryObjects = [(deliveryObject){
   id = "0bf003ee0000000000000000000002a11cb6"
   start = 2019-01-02 09:30:00
   messageId = "68027b94b892396ed29581cde9ad07ff"
   status = "sent"
   type = "normal"
   }, (deliveryObject){
   id = "0bf0BE3ABFFDF8744952893782139E82793B"
   start = 2018-12-29 23:00:00
   messageId = "0bc403eb0000000000000000000000113404"
   status = "sent"
   type = "transactional"
 }, (deliveryObject){
   id = "0bf0702D03CB42D848CBB0B0AF023A87FA65"
   start = 2018-12-29 23:00:00
   messageId = "0bc403eb0000000000000000000000113403"
   status = "sent"
   type = "transactional"
   }
]


data = [Client.dict(suds_object) for suds_object in list_of_deliveryObjects]
df = pd.DataFrame(data)

Answer 3

我这样做：

import pandas as pd
lst =[{
   'id':"0bf003ee0000000000000000000002a11cb6",
   'start' : "2019-01-02 09:30:00",
   'messageId': "68027b94b892396ed29581cde9ad07ff",
   'status' : "sent",
   'type' : "normal"
   },{
   'id' :  "0bf0BE3ABFFDF8744952893782139E82793B",
   'start' :  "2018-12-29 23:00:00",
   'messageId' :  "0bc403eb0000000000000000000000113404",
   'status' :  "sent",
   'type' :  "transactional"
 }, {
   'id' :  "0bf0702D03CB42D848CBB0B0AF023A87FA65",
   'start' :  "2018-12-29 23:00:00",
   'messageId' :  "0bc403eb0000000000000000000000113403",
   'status' :  "sent",
   'type' :  "transactional"
   }]
df = pd.DataFrame(lst)
df

并得到了这个（也参见附件图片）：

    id  messageId   start   status  type
0   0bf003ee0000000000000000000002a11cb6    68027b94b892396ed29581cde9ad07ff    2019-01-02 09:30:00 sent    normal
1   0bf0BE3ABFFDF8744952893782139E82793B    0bc403eb0000000000000000000000113404    2018-12-29 23:00:00 sent    transactional
2   0bf0702D03CB42D848CBB0B0AF023A87FA65    0bc403eb0000000000000000000000113403    2018-12-29 23:00:00 sent    transactional

结果