我向一个函数发送了 3 个值，但在函数之后我只想再次测试第 3 个函数返回。 我怎样才能做到这一点？

Question

rows = 22
rowsMax = 21
columns = 117
columnMax = 117
status = "True"

def DrawBoard (rows,columns,status):
  if rows > rowsMax or columns > columnMax:
     status = "False"
     rows = 0
     columns = 0
  return rows,columns,status


DrawBoard(rows,columns,status)


# I want to test only the status returns from the function but get error
# DrawBoard() missing 2 required positional arguments: 'columns' and 'status'.
if DrawBoard(status) == "False":
  print("Either the row and columns maximum were excepted")

Answer 1

如果您编写DrawBoard(.., .., ..)那是一个函数调用，因此您正在调用该函数并返回其返回值。 要保存这些值，您可以这样做

ret1, ret2, ret3 = DrawBoard(rows, columns, status)

现在检查第三个值

if ret3 == False:

您还可以直接访问第三个返回值，而无需使用DrawBoard(rows, columns, status)[2]将它们存储在变量中。

Answer 2

推送到对象版本：

class Board:

    def __init__(self, rows, rowsMax, columns, columnMax):
        self.rows = rows
        self.rowsMax = rowsMax
        self.columns = columns
        self.columnMax = columnMax
        self.status = True

    def drawBoard(self):
        msgError = 'Either the row and columns maximum were excepted'
        if self.rows > self.rowsMax or self.columns > self.columnMax:
            self.status = False
            self.rows = 0
            self.columns = 0
        else:
            msgError = 'All fine!'

        return msgError


if __name__ == '__main__':
    newBoard = Board(22, 21, 117, 117)
    print(newBoard.drawBoard())  # Either the row and columns maximum were excepted
    print(newBoard.status)  # False

    newBoard = Board(20, 21, 117, 117)
    print(newBoard.drawBoard())  # All fine!
    print(newBoard.status)  # True

访问状态就像self.status在类中的 True 或 False 一样简单，或者使用带有newBoard.status的对象......