如何让我的第一个输入无效

Question

基本上，当我运行代码时，如果我为第一个输入输入了一个无效的答案，它仍然会继续到第二个输入。 如果我为第一个输入输入无效答案，我正在尝试获取它它再次启动循环。 （对不起，我很新）

play_again = "y"


# Collects both players name and gives error if not alphabet
while play_again == "y":
    def setup():enter code here
        playerOne = input("What is player 1's name: ")
        playerTwo = input("What is player 2's name: ")
        if playerOne.isalpha() == True and playerTwo.isalpha() == True:
            print("Valid names")
    
        else:
            print("Invalid name")
setup

Answer 1

您正在检查玩家一和二在进入后同时无效。 您的代码从上到下运行，因此在检查是否有效之前需要两个输入。 您可以通过替换它来解决此问题。

playerOne = input(...)
if playerOne.isalpha():
   Print("name 1 is valid")
Else:
   Print("name is invalid please try again")
   # here you have some options you could end your program using exit() or put this method in a loop to keep asking for a new name pick one and add it in and it will repeat the check
player two = ... # you get the point just rewrite your previous code

只需询问您是否需要我提到的任何选项的任何帮助。