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R 中数据帧的空间子集

[英]Spatial subset of data frame in R

我有一个使用plot()绘制的大数据框。 然后我用:

library(splancs) 

polygon_xy = getpoly(quiet=FALSE) 

并在 plot 到 select 我感兴趣的区域上画了点。 这生成了我绘制的多边形的 x,y 坐标。

我想提取位于多边形内的数据,或者将我的 df 子集化以仅包含位于多边形内的点。 任何建议如何做到这一点?

当您使用plot并让getpoly识别坐标时,点数据需要采用特定格式(即带有 x 和 y 的矩阵)。

library(splancs)
library(tidyverse)
library(sf)

set.seed(543)
xy <-
  cbind(x = runif(n = 25, min = -118, max = -117),
        y = runif(n = 25, min = 40, max = 42))

plot(xy)

# Draw a polygon for study area.
poly <- getpoly()

# Convert to sf objects.
polysf <- st_as_sf(as.data.frame(poly), coords = c("V1", "V2"), crs = 4326) %>% 
  dplyr::summarise() %>%
  st_cast("POLYGON") %>% 
  st_convex_hull()

xysf <- st_as_sf(as.data.frame(xy), coords = c("x", "y"), crs = 4326)

# Do an intersection to keep only points inside the drawn polygon.
xy_intersect <- st_intersection(polysf, xysf)

Output

Simple feature collection with 9 features and 0 fields
Geometry type: POINT
Dimension:     XY
Bounding box:  xmin: -117.7913 ymin: 40.82405 xmax: -117.4264 ymax: 41.7448
Geodetic CRS:  WGS 84
                    geometry
1 POINT (-117.4264 41.18712)
2  POINT (-117.5756 41.7448)
3 POINT (-117.7913 40.82405)
4 POINT (-117.7032 41.15077)
5 POINT (-117.5634 41.23936)
6 POINT (-117.7441 40.84163)
7  POINT (-117.692 41.27514)
8 POINT (-117.6864 40.98462)
9 POINT (-117.5759 40.88477)

library(mapview)中的mapview::mapview(xy_intersect)绘制

在此处输入图像描述

但是,如果您想从原始 dataframe 中提取行,那么这里有另一个技巧,用于提取落在绘制多边形内的点(例如,当多边形坐标看起来像 0.003456 时)。

library(splancs)
library(tidyverse)

set.seed(543)
xy <-
  cbind(x = runif(n = 25, min = -118, max = -117),
        y = runif(n = 25, min = 40, max = 42))

plot(xy)

# Draw a polygon for study area.
poly <- getpoly()

# Plot the results.
plot(xy)
polygon(poly)

# This will return a logical vector for points in the polygon
io <- inout(xy, poly)
points(xy[io,], pch = 16, col = "blue")

# Then, can use the index from io to extract the points that 
# are inside the polygon from the original set of points.
extract_points <- as.data.frame(xy)[which(io == TRUE),]

extract_points

Output

           x        y
2  -117.4506 41.17794
3  -117.4829 40.71030
8  -117.4679 40.71702
19 -117.3354 40.53687
21 -117.5219 40.47077
22 -117.4876 40.18188
25 -117.2015 40.86243

在此处输入图像描述

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