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如何在Pandas Dataframe中迭代計數

[英]How to iteratively count in Pandas Dataframe

我想一直計數一個值,直到pandas / python中的當前位置為止。 必須考慮一個條件(“得分”列中必須存在數字,才能將游戲計為已玩游戲;如果我讀取的excel文件中沒有值,則顯示為NaN)。

下面的代碼是我的位置:

import pandas as pd


df = pd.read_excel('G:\Project\SOQ1.xlsx')

df['date'] = pd.to_datetime(df['date'])

df = df.sort(columns='date')

df = df.set_index('date')

def calc_all_count(team_name):  
    home_count = df['home'].value_counts().get(team_name, 0)
    away_count = df['away'].value_counts().get(team_name, 0)
    all_count = home_count + away_count
    return all_count

def calc_home_count(team_name):    
    home_count = df['home'].value_counts().get(team_name, 0)
    return home_count

def calc_away_count(team_name):
    away_count = df['away'].value_counts().get(team_name, 0)
    return away_count

df['hag'] = df['home'].map(calc_all_count)
df['aag'] = df['away'].map(calc_all_count)
df['hahg'] = df['home'].map(calc_home_count)
df['aaag'] = df['away'].map(calc_away_count)

print df


                    league home away  hscore  ascore  hag  aag  hahg  aaag
date                                                                      
2015-01-03 03:02:00    MLB  Cle  Tex       9       6    3   15     2     7
2015-05-10 03:03:00    MLB  Bos  Cle       6       7   16    3     7     1
2015-10-15 03:00:00    MLB  Tex  Bos       5       2   15   16     8     9
2015-10-15 03:30:00    MLB  Tex  Bos       1       6   15   16     8     9
2015-10-16 00:00:00    MLB  Tex  Bos       4       4   15   16     8     9
2015-10-17 03:30:00    MLB  Bos  Tex       2       8   16   15     7     7
2015-10-18 00:00:00    MLB  Tex  Bos       9      10   15   16     8     9
2015-10-20 00:00:00    MLB  Bos  Tex       2       3   16   15     7     7
2015-10-21 00:00:00    MLB  Tex  Bos       5       1   15   16     8     9
2015-10-22 03:00:00    MLB  Tex  Bos       5       3   15   16     8     9
2015-10-23 00:00:00    MLB  Bos  Tex       3       4   16   15     7     7
2015-10-25 23:00:00    MLB  Bos  Tex       6       6   16   15     7     7
2015-10-25 23:00:00    MLB  Bos  Tex       5       1   16   15     7     7
2015-10-26 00:00:00    MLB  Tex  Bos       9       6   15   16     8     9
2015-10-27 01:30:00    MLB  Bos  Tex      10       5   16   15     7     7
2015-10-28 01:00:00    MLB  Tex  Bos     NaN     NaN   15   16     8     9
2015-11-20 03:01:00    MLB  Cle  Bos     NaN     NaN    3   16     2     9

我想要的是每個游戲之前沒有玩過的游戲。 因此,由於沒有人玩過,因此第一局/每行的所有數字都應讀為0。 應該看起來像這樣:

                    league home away  hscore  ascore  hag  aag  hahg  aaag
date                                                                      
2015-01-03 03:02:00    MLB  Cle  Tex       9       6    0    0     0     0
2015-05-10 03:03:00    MLB  Bos  Cle       6       7    0    1     0     0
2015-10-15 03:00:00    MLB  Tex  Bos       5       2    1    1     0     0
2015-10-15 03:30:00    MLB  Tex  Bos       1       6    2    2     1     1
2015-10-16 00:00:00    MLB  Tex  Bos       4       4    3    3     2     2
2015-10-17 03:30:00    MLB  Bos  Tex       2       8    4    4     1     1
2015-10-18 00:00:00    MLB  Tex  Bos       9      10    5    5     3     3
2015-10-20 00:00:00    MLB  Bos  Tex       2       3    6    6     2     2
2015-10-21 00:00:00    MLB  Tex  Bos       5       1    7    7     4     4
2015-10-22 03:00:00    MLB  Tex  Bos       5       3    8    8     5     5
2015-10-23 00:00:00    MLB  Bos  Tex       3       4    9    9     3     3
2015-10-25 23:00:00    MLB  Bos  Tex       6       6   10   10     4     4
2015-10-25 23:00:00    MLB  Bos  Tex       5       1   11   11     5     5
2015-10-26 00:00:00    MLB  Tex  Bos       9       6   12   12     6     6
2015-10-27 01:30:00    MLB  Bos  Tex      10       5   13   13     6     6
2015-10-28 01:00:00    MLB  Tex  Bos     NaN     NaN   14   14     7     7
2015-11-20 03:01:00    MLB  Cle  Bos     NaN     NaN    2   14     1     7

我該如何計算“之前”的當前位置? 我想我應該使用.iloc或.ix,但我不知道。

任何幫助實現此或更好的代碼表示贊賞。 提出這個問題的技巧也更好。

我的方法不使用map ,但是函數stackgroupbypivot_tablemergecumsum

df.sort_values(by='date', axis=0, inplace = True)
#set helper column for counting cumsum
df['one'] = 1
print df
#                   date league home away  hscore  ascore  one
#5   2015-01-03 03:02:00    MLB  Cle  Tex       9       6    1
#0   2015-05-10 03:03:00    MLB  Bos  Cle       6       7    1
#1   2015-10-15 03:00:00    MLB  Tex  Bos       5       2    1
#2   2015-10-15 03:30:00    MLB  Tex  Bos       1       6    1
#3   2015-10-16 00:00:00    MLB  Tex  Bos       4       4    1
#4   2015-10-17 03:30:00    MLB  Bos  Tex       2       8    1
#6   2015-10-18 00:00:00    MLB  Tex  Bos       9      10    1
#7   2015-10-20 00:00:00    MLB  Bos  Tex       2       3    1
#8   2015-10-21 00:00:00    MLB  Tex  Bos       5       1    1
#9   2015-10-22 03:00:00    MLB  Tex  Bos       5       3    1
#10  2015-10-23 00:00:00    MLB  Bos  Tex       3       4    1
#11  2015-10-25 23:00:00    MLB  Bos  Tex       6       6    1
#12  2015-10-25 23:00:00    MLB  Bos  Tex       5       1    1
#13  2015-10-26 00:00:00    MLB  Tex  Bos       9       6    1
#14  2015-10-27 01:30:00    MLB  Bos  Tex      10       5    1
#15  2015-10-28 01:00:00    MLB  Tex  Bos     NaN     NaN    1
#16  2015-11-20 03:01:00    MLB  Cle  Bos     NaN     NaN    1
#set columns home and away to one columns for cumsum
df2 = df[['date', 'home', 'away', 'one']].set_index(['date', 'one'])
df2 = df2.stack().reset_index(name="both")
df2['new'] =  df2.groupby(['both'])['one'].cumsum() - 1
#print df2

#get back to original index
df1 = pd.pivot_table(df2, index=['date'], columns=['level_2'], values='new').reset_index()
#print df1

#merge with original df
df1 = pd.merge(df, df1, on=['date'], suffixes=('', '_new'))

#rename and casr float columns to integers columns
df1 = df1.rename(columns={'away_new':'aag', 'home_new':'hag',})
df1['aag'] = df1['aag'].astype(int)
df1['hag'] = df1['hag'].astype(int)

#count aaag and hahg
df1['aaag'] =  df1.groupby(['away'])['one'].cumsum() - 1
df1['hahg'] =  df1.groupby(['home'])['one'].cumsum() - 1

#drop helper column one and set index
df1 = df1.drop(['one'], axis=1 ).set_index('date')
#reorder columns
df1 = df1[['league', 'home', 'away', 'hscore', 'ascore', 'hag', 'aag', 'hahg', 'aaag']]
print df1
                    league home away  hscore  ascore  hag  aag  hahg  aaag
date                                                                      
2015-01-03 03:02:00    MLB  Cle  Tex       9       6    0    0     0     0
2015-05-10 03:03:00    MLB  Bos  Cle       6       7    0    1     0     0
2015-10-15 03:00:00    MLB  Tex  Bos       5       2    1    1     0     0
2015-10-15 03:30:00    MLB  Tex  Bos       1       6    2    2     1     1
2015-10-16 00:00:00    MLB  Tex  Bos       4       4    3    3     2     2
2015-10-17 03:30:00    MLB  Bos  Tex       2       8    4    4     1     1
2015-10-18 00:00:00    MLB  Tex  Bos       9      10    5    5     3     3
2015-10-20 00:00:00    MLB  Bos  Tex       2       3    6    6     2     2
2015-10-21 00:00:00    MLB  Tex  Bos       5       1    7    7     4     4
2015-10-22 03:00:00    MLB  Tex  Bos       5       3    8    8     5     5
2015-10-23 00:00:00    MLB  Bos  Tex       3       4    9    9     3     3
2015-10-25 23:00:00    MLB  Bos  Tex       6       6   10   10     4     4
2015-10-25 23:00:00    MLB  Bos  Tex       5       1   10   10     5     5
2015-10-26 00:00:00    MLB  Tex  Bos       9       6   12   12     6     6
2015-10-27 01:30:00    MLB  Bos  Tex      10       5   13   13     6     6
2015-10-28 01:00:00    MLB  Tex  Bos     NaN     NaN   14   14     7     7
2015-11-20 03:01:00    MLB  Cle  Bos     NaN     NaN    2   15     1     8

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