將2D字符串數組轉換為2D int數組（多維數組）

Question

我想替換string[,] 2D數組

public static readonly string[,] first =
{
    {"2", " ", " ", " ", "1"},
    {"2", " ", "4", "3", " "},
    {" ", "2", " ", "1", " "},
    {" ", "1", " ", "3", " "},
    {"1", " ", " ", " ", " "}
};

到int[,]數組中

int X=-1;
public static readonly int[,] second =  
{
    {2, X, X, X, 1},
    {2, X, 4, 3, X},
    {X, 2, X, 1, X},
    {X, 1, X, 3, X},
    {1, X, X, X, X}
};

是否可以將string[,]數組轉換為int[,]數組？ 如果是，如何將string[,]轉換為int[,] ？ 謝謝。

Answer 1

string[,] first =
{
    {"2", " ", " ", " ", "1"},
    {"2", " ", "4", "3", " "},
    {" ", "2", " ", "1", " "},
    {" ", "1", " ", "3", " "},
    {"1", " ", " ", " ", " "}
};


int[,] second = new int[first.GetLength(0), first.GetLength(1)];
int x = -1;
for (int i = 0; i < first.GetLength(0); i++)
{
    for (int j = 0; j < first.GetLength(1); j++)
    {
        second[i, j] = string.IsNullOrWhiteSpace(first[i, j]) ? x : Convert.ToInt32(first[i, j]);
    }
}

Answer 2

現場示例： Ideone

public static readonly string[,] first =
{
     {"2", " ", " ", " ", "1"},
     {"2", " ", "4", "3", " "},
     {" ", "2", " ", "1", " "},
     {" ", "1", " ", "3", " "},
     {"1", " ", " ", " ", " "}
};

轉換 （請注意，當字符串= " " ，我改為使用0 ） ：

int[,] second = new int[first.GetLength(0), first.GetLength(1)];

for (int j = 0; j < first.GetLength(0); j++)    
{
    for (int i = 0; i < first.GetLength(1); i++)
    {
        int number;
        bool ok = int.TryParse(first[j, i], out number);
        if (ok)
        {
            second[j, i] = number;
        }
        else
        {
            second[j, i] = 0;
        }
    }
}

Answer 3

假設X = -1：

private static int[,] ConvertToIntArray(string[,] strArr)
{
    int rowCount = strArr.GetLength(dimension: 0);
    int colCount = strArr.GetLength(dimension: 1);

    int[,] result = new int[rowCount, colCount];
    for (int r = 0; r < rowCount; r++)
    {
        for (int c = 0; c < colCount; c++)
        {
            int value;
            result[r, c] = int.TryParse(strArr[r, c], out value) ? value : -1;
        }
    }
    return result;
}

Answer 4

使用您正在使用的循環，並將空字符串替換為null值，如果要使用此數組，只需檢查該值是否不為null。