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[英]Volume of a part of a sphere cutted using 3 planes using R-Language (integral)
[英]separate grouping by months using R-Language
使用dput
,我提供數據。
df <-
structure(list(Goods = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L,
2L, 2L, 2L, 2L, 2L, 2L),
.Label = c("IceScream", "Kex"), class = "factor"),
date = structure(c(1L, 1L, 2L, 2L, 2L, 3L, 3L, 3L, 3L, 3L, 3L,
3L, 4L, 4L, 1L, 1L, 2L, 2L, 2L, 3L, 3L, 3L,
3L, 3L, 3L, 3L, 4L, 4L),
.Label = c("12.01.2015", "13.01.2015",
"14.01.2015", "15.01.2015"), class = "factor"),
Y = c(200L, 50L, 100L, 50L, 200L, 200L, 50L, 200L, 100L, 1000L,
1000L, 50L, 50L, 100L, 200L, 50L, 23L, 50L, 200L, 200L,
45L, 200L, 100L, 6L, 23L, 50L, 50L, 436L)),
.Names = c("Goods", "date", "Y"), class = "data.frame",
row.names = c(NA, -28L))
我想按月匯總數據。
library(dplyr)
library(lubridate)
library(zoo)
df <- df %>%
group_by(yearMon = as.yearmon(dmy(date))) %>%
summarise(new = sum(new))
但是我有一組商品(冰淇淋和凱克斯)。 每個小組如何按月匯總?
像這樣
Goods date Y
IceScream jan-2015 3350
Kex jan-2015 1633
好的,我看到您實際上想按Y的數量來總結,這很不好:
df2<-df %>% group_by( yearMon = as.yearmon(dmy(date)), Goods ) %>%
summarise(new = sum(Y))
df2
# A tibble: 2 x 3
# Groups: yearMon [?]
yearMon Goods new
<S3: yearmon> <fct> <int>
1 Jan 2015 IceScream 3350
2 Jan 2015 Kex 1633
如果要按周匯總,請使用:
df2 <- df %>% group_by(Goods,week = week(dmy(date)), ) %>% summarise(new =sum(Y))
這使:
> df2
# A tibble: 4 x 3
# Groups: Goods [?]
Goods week new
<fct> <dbl> <int>
1 IceScream 2 3200
2 IceScream 3 150
3 Kex 2 1147
4 Kex 3 486
>
也許這使用base
功能而不是其他軟件包( dplyr
除外):
df %>%
group_by(Goods, yearMon = format(as.Date(date,'%d.%m.%Y'),'%b-%Y')) %>%
summarise(new = sum(Y))
# A tibble: 2 x 3
# Groups: Goods [?]
Goods yearMon new
<fct> <chr> <int>
1 IceScream jan-2015 3350
2 Kex jan-2015 1633
編輯
更基本的:
df$yearMon <- format(as.Date(df$date,'%d.%m.%Y'),'%b-%Y')
aggregate(cbind(Y) ~ Goods + yearMon, data = df, sum, na.rm = TRUE)
Goods yearMon Y
1 IceScream gen-2015 3350
2 Kex gen-2015 1633
編輯2:
要以每周的1月1日為准,您可以嘗試以下操作:
library(lubridate)
df %>%
group_by(Goods, week =paste(ceiling(day(as.Date(date,'%d.%m.%Y')) / 7),month(as.Date(date,'%d.%m.%Y'), label = TRUE, abbr = TRUE),sep='-')
) %>%
summarise(new = sum(Y))
# A tibble: 4 x 3
# Groups: Goods [?]
Goods week new
<fct> <chr> <int>
1 IceScream 2-jan 3200
2 IceScream 3-jan 150
3 Kex 2-jan 1147
4 Kex 3-jan 486
使用sqldf
:
df$date= as.POSIXct(df$date, format="%d.%m.%Y") # Convert date to POSIXct
df$date=format(as.Date(df$date), "%Y-%m") # Extract year and month
library(sqldf) # Using sqldf group by date and Goods
sqldf("select Goods,date,sum(Y) from df group by date,Goods")
輸出:
Goods date sum(Y)
1 IceScream 2015-01 3350
2 Kex 2015-01 1633
如果不確定要如何匯總日期,請首先使用周,月和年以及thenn創建單獨的列,以便更輕松地測試不同的版本:
library(dplyr)
library(lubridate)
df <- df %>%
mutate(date = dmy(date),
week = week(date),
month = month(date, label = T),
year = year(date))
df
# Goods date Y week month year
# 1 IceScream 2015-01-12 200 2 Jan 2015
# 2 IceScream 2015-01-12 50 2 Jan 2015
# 3 IceScream 2015-01-13 100 2 Jan 2015
# 4 IceScream 2015-01-13 50 2 Jan 2015
# 5 IceScream 2015-01-13 200 2 Jan 2015
# 6 IceScream 2015-01-14 200 2 Jan 2015
僅按年份和月份分組:
df %>%
group_by(Goods, year, month) %>%
summarise(sum_y = sum(Y))
# A tibble: 2 x 4
# Groups: Goods, year [?]
# Goods year month sum_y
# <fct> <dbl> <ord> <int>
# 1 IceScream 2015 Jan 3350
# 2 Kex 2015 Jan 1633
按年份月份和星期分組:
df %>%
group_by(Goods, year, month, week) %>%
summarise(sum_y = sum(Y))
# A tibble: 4 x 5
# Groups: Goods, year, month [?]
# Goods year month week sum_y
# <fct> <dbl> <ord> <dbl> <int>
# 1 IceScream 2015 Jan 2 3200
# 2 IceScream 2015 Jan 3 150
# 3 Kex 2015 Jan 2 1147
# 4 Kex 2015 Jan 3 486
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