Python定義多模態函數

Question

我不需要創建一個函數來判斷：

• 沒有模式
• 有 1 種模式
• 如果是多模式列表

我得到了前 2 分的封面：

lista = [1,2,2,3,3,4]
contador = {}

for i in lista:
    cuenta = lista.count(i)
    contador[i] = cuenta

maximo =(0)
moda = [0]

for i in contador:
    if(contador[i]>maximo):
        maximo = contador[i]
        moda = i
        freq = contador[i]


if maximo == 1:
    print("There is no mode")
else:
    print ("Mode is: %d, with a frequency of: %d" % (moda, freq))

但是我正在努力尋找一種方法來定義列表是否是多模式的。 我想首先定義哪個頻率最高，然后檢查contador以取出下面的所有頻率，但它似乎不起作用：

for i in contador:
    if contador[i] < max:
        delete = [i]
        del contador[delete]

關於如何做到這一點的任何想法？

謝謝

Answer 1

對於多模態，您需要檢查最大頻率並計算頻率計數。 如果它是 1 則表示沒有模式，超過 1 並且正好是 1 則有 1 種模式，並且 i 頻率計數大於 1 並且有多個值具有相同的計數那么它是多模態的

lista = [1,2,3,3,4]

res  = {}
for i in lista:
    if i not in res.keys():
        res[i]=1
    else:
        res[i]+=1
freq = res.values()
max_freq = max(freq)
if max_freq==1:
    print('no mode')
else:
    key = ''
    if list(freq).count(max_freq)==1:
        for k, v in res.items():
            if v==max_freq:
                print('mode is {}, frequency is {}'.format(k, max_freq))
                break
    else:
        print('multimodeal')
        for k, v in res.items():
            if v==max_freq:
                print('mode is {}, frequency is {}'.format(k, max_freq))

Answer 2

對現有代碼的最簡單修改如下：

maximo = 0
moda = []

for i in contador:
    if(contador[i] > maximo):
        maximo = i
        freq = contador[i]
        moda = []
    if(contador[i]==freq):
        moda.append(i)

並將最終print更改為：

print ("Mode is: %s, with a frequency of: %d" % (moda, freq))

使用庫函數簡化了整個過程：

from collections import Counter

lista = [1, 2, 2, 3, 3, 4]

contador = Counter(lista)
# get the second part (the count) from the first element of the first most common element
freq = contador.most_common(1)[0][1]
# get all the x's for which the count is freq
moda = [x for x, c in contador.items() if c == freq]

if freq == 1:
    print("There is no mode")
else:
    print("Mode is: %s, with a frequency of: %d" % (moda, freq))

Answer 3

def moda(x):
    input_string = input("Lista de numeros separados por un espacio: ")
    lista = input_string.split()
    contador = {}
    for i in lista:
        cuenta = lista.count(i)
        contador[i] = cuenta
    maximo =(0)
    for i in contador:
        if(contador[i]>maximo):
            maximo = contador[i]
        modas = {}
        for i in contador:
            if contador[i] == maximo:
                modas[i] = contador[i]
    if maximo == 1:
        return("No hay modas")
    elif len(modas)>1:
        return ("Las modas y sus frecuencias son:")
        return (modas)
    else:
        return ("la moda y su frecuencia es:")
        return (modas)