[英]Find optimal Lasso/L1 regularization strength using cross validation for logistic regression in scikit learn
[英]Logistic Regression Model using Regularization (L1 / L2) Lasso and Ridge
我正在嘗試構建 model 並創建網格搜索,下面是代碼。 原始數據是從該站點下載的(信用卡欺詐數據)。 https://www.kaggle.com/mlg-ulb/creditcardfraud
讀取數據后從標准化開始的代碼。
standardization = StandardScaler()
credit_card_fraud_df[['Amount']] = standardization.fit_transform(credit_card_fraud_df[['Amount']])
# Assigning feature variable to X
X = credit_card_fraud_df.drop(['Class'], axis=1)
# Assigning response variable to y
y = credit_card_fraud_df['Class']
# Splitting the data into train and test
X_train, X_test, y_train, y_test = train_test_split(X, y, train_size=0.7, test_size=0.3, random_state=100)
X_train.head()
power_transformer = PowerTransformer(copy=False)
power_transformer.fit(X_train) ## Fit the PT on training data
X_train_pt_df = power_transformer.transform(X_train) ## Then apply on all data
X_test_pt_df = power_transformer.transform(X_test)
y_train_pt_df = y_train
y_test_pt_df = y_test
train_pt_df = pd.DataFrame(data=X_train_pt_df, columns=X_train.columns.tolist())
# set up cross validation scheme
folds = StratifiedKFold(n_splits = 5, shuffle = True, random_state = 4)
# specify range of hyperparameters
params = {"C":np.logspace(-3,3,5,7), "penalty":["l1","l2"]}# l1 lasso l2 ridge
## using Logistic regression for class imbalance
model = LogisticRegression(class_weight='balanced')
grid_search_cv = GridSearchCV(estimator = model, param_grid = params,
scoring= 'roc_auc',
cv = folds,
return_train_score=True, verbose = 1)
grid_search_cv.fit(X_train_pt_df, y_train_pt_df)
## reviewing the results
cv_results = pd.DataFrame(grid_search_cv.cv_results_)
cv_results
示例結果:
mean_fit_time std_fit_time mean_score_time std_score_time param_C param_penalty params split0_test_score split1_test_score split2_test_score split3_test_score split4_test_score mean_test_score std_test_score rank_test_score
0 0.044332 0.002040 0.000000 0.000000 0.001 l1 {'C': 0.001, 'penalty': 'l1'} NaN NaN NaN NaN NaN NaN NaN 6
1 0.477965 0.046651 0.016745 0.003813 0.001 l2 {'C': 0.001, 'penalty': 'l2'} 0.485714 0.428571 0.542857 0.485714 0.457143 0.480000 0.037904 5
我在輸入數據中沒有任何 null 值。我不明白為什么我得到這些列的 Nan 值。 誰能幫幫我嗎?
您在此處定義的默認求解器有問題:
model = LogisticRegression(class_weight='balanced')
這是從以下錯誤消息中得出的:
ValueError: Solver lbfgs supports only 'l2' or 'none' penalties, got l1 penalty.
此外,在定義參數網格之前研究文檔可能會有用:
penalty: {'l1', 'l2', 'elasti.net', 'none'}, default='l2' 用於指定懲罰中使用的范數。 “newton-cg”、“sag”和“lbfgs”求解器僅支持 l2 懲罰。 “elasti.net”僅受“saga”求解器支持。 如果為“無”(liblinear 求解器不支持),則不應用正則化。
一旦您使用支持所需網格的不同求解器更正它,您就可以達到 go:
## using Logistic regression for class imbalance
model = LogisticRegression(class_weight='balanced', solver='saga')
grid_search_cv = GridSearchCV(estimator = model, param_grid = params,
scoring= 'roc_auc',
cv = folds,
return_train_score=True, verbose = 1)
grid_search_cv.fit(X_train_pt_df, y_train_pt_df)
## reviewing the results
cv_results = pd.DataFrame(grid_search_cv.cv_results_)
還要注意ConvergenceWarning
,它可能建議您需要增加默認max_iter
、 tol
或切換到另一個求解器並重新考慮所需的參數網格。
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