[英]Best way to optimize if with three unknowns?
我制作了這段代碼來生成密碼作為練習,但我想知道是否有更聰明的方法來使用if
。 愚蠢地列出所有可能的情況,我感到很糟糕。 if
變得難以理解,則嘗試將if
放在其他人中。
import random
import re
import exrex
len_pwd = int(input('Length of the password : '))
upc = int(input('Upper case ? (0 = No ; 1 = Yes) : '))
nbr = int(input('Numbers ? (0 = No ; 1 = Yes) : '))
spe = int(input('Special char ? (0 = No ; 1 = Yes) : '))
pwd = ''
for i in range(len_pwd):
if upc and not nbr and not spe:
a = exrex.getone('[a-zA-Z]')
pwd += a
elif nbr and not upc and not spe:
a = exrex.getone('[a-z\d]')
pwd += a
elif spe and not upc and not nbr:
a = exrex.getone('[a-z"_$.+-/*=]')
pwd += a
elif nbr and spe and not upc:
a = exrex.getone('[a-z\d"_$.+-/*=]')
pwd += a
elif upc and nbr and not spe:
a = exrex.getone('[a-zA-Z\d]')
pwd += a
elif upc and spe and not nbr:
a = exrex.getone('[a-zA-Z"_$.+-/*=]')
pwd += a
elif not upc and not nbr and not spe:
print("Don't bother me.")
break
else:
a = exrex.getone('[a-zA-Z\d"_$.+-/*=]')
pwd += a
print(pwd)
謝謝:另外,如果代碼中的其他內容很丑,請告訴我)
您可以根據輸入構建正則表達式字符串:
reg = '[a-z'
if upc: reg += "A-Z"
if nbr: reg += "\\d"
if spe: reg += "_$.+-/*="
reg += "]"
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