[英]How to proportionally (respecting aspect ratio) scale a rectangle?
我想簡單地給定的盒子x
的y
和規模時,通過設置x
和查找y
,反之亦然。 如何用Python表達這個公式(為了便於閱讀)。 我試圖將這個盒子放在一個更大的盒子里面,這樣內盒子總能放在更大的盒子里面。
new_y = (float(new_x) / x) * y
要么
new_x = (float(new_y) / y) * x
注意:我不是真的做Python,所以這是偽代碼。
您需要的是兩個框的相對寬高比,因為它確定哪個新軸必須與新框的大小相同:
r_old = old_w / old_h
r_new = new_w / new_h
if (r_old > r_new) then
w = new_w // width of mapped rect
h = w / r_old // height of mapped rect
x = 0 // x-coord of mapped rect
y = (new_h - h) / 2 // y-coord of centered mapped rect
else
h = new_h
w = h * r_old
y = 0
x = (new_w - w) / 2
endif
>>> import fractions
>>> x, y = 10, 10
>>> fix_rat = fractions.Fraction(x, y)
>>> fix_rat
Fraction(1, 1)
>>> x = 8
>>> if fractions.Fraction(x, y) != fix_rat:
y = x / fix_rat #well instead of y you should put the last one that has been changed
#but this is just an example
>>> y
Fraction(8, 1)
>>>
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