[英]Doubling and dividing floating point values
I have the function which I believe will convert an int into a floating point value split into the sign exponent and fraction components of the value. 我有一个函数,我相信将int转换为浮点值,拆分为值的符号指数和分数组成部分。 Using IEEE 754 to represent Float values.
使用IEEE 754表示浮点值。
unsigned test(unsigned x) {
// split the given bits of sign exponent and fraction, combine to return
unsigned int sign = (x & 0x80000000) >> 31;
unsigned int expo = (x & 0x7F800000) >> 23;
unsigned int frac = (x & 0x007fffff);
return (sign << 31) | (expo << 23) | frac;
}
I'm unsure however how I could compute the halved or doubled values from this floating point representation. 但我不确定如何从这个浮点表示计算减半或加倍的值。
unsigned doubled(unsigned x) {
// get float
// float = unsigned int to float
// doubleFloat = 2*f
// if float is not a number
// return unsigned float
// else return unsigned integer of half float
unsigned int sign = (x & 0x80000000) >> 31;
unsigned int expo = (x & 0x7F800000) >> 23;
unsigned int frac = (x & 0x007fffff);
if (expo == 0xff)
return uf;
else ...
}
It seems that you are using IEEE 754 to represent Float values. 您似乎使用IEEE 754来表示Float值。
If you want to double the binary representation, you just need to increment by 1 the expoent. 如果要将二进制表示加倍,则只需要将expoent加1。 The same is true if you want to half, just decrement by 1
如果你想减半,只减1,也是如此
Remember that this is true only if your number is in normal range, including even after doubling or halving 请记住,只有当您的号码在正常范围内时才会出现这种情况,包括即使在加倍或减半之后也是如此
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