从3D Matrix中提取补丁

Question

I have a 3D matrix A of dimensions hxwxc . I want to extract patches of dimensions ph x pw from each "channel" c . ph divides h and pw divides w . In this example,

h x w x c = 4 x 4 x 3
ph x pw = 2 x 2

I know how to do this in tensorflow using gather_nd but I was hoping for something more efficient in terms of setting it up, because the dimensions will be big and I'd rather not have the indices array of gather_nd in memory. Is there possibly an intelligent reshape? Either numpy or tensorflow solution would be very nice!

Answer 1

You could use some reshaping and swapping of axes -

A.reshape(h//ph,ph,w//pw,pw,-1).swapaxes(1,2)

Sample run -

In [46]: # Sample inputs
    ...: h,w,c = 10,12,3
    ...: ph, pw = 2,2
    ...: A = np.random.randint(0,9,(h,w,c))
    ...: 

In [47]: A.reshape(h//ph,ph,w//pw,pw,-1).swapaxes(1,2).shape
Out[47]: (5, 6, 2, 2, 3)

Each element (as block) along first two axes represent the patches. Thus. for the sample provided, we would have 5 x 6 = 30 patches.

If you want those patches along one merged first axis, use one more reshape -

In [85]: out = A.reshape(h//ph,ph,w//pw,pw,-1).swapaxes(1,2).reshape(-1,ph,pw,c)

In [86]: out.shape
Out[86]: (30, 2, 2, 3)

Let's verify by manually inspecting values themselves -

In [81]: A[:ph,:pw] # First patch
Out[81]: 
array([[[6, 5, 2],
        [4, 0, 1]],

       [[0, 0, 4],
        [2, 3, 0]]])

In [82]: A[:ph,pw:2*pw] # Second patch
Out[82]: 
array([[[8, 3, 3],
        [0, 0, 2]],

       [[8, 5, 4],
        [3, 4, 6]]])

In [83]: out[0]
Out[83]: 
array([[[6, 5, 2],
        [4, 0, 1]],

       [[0, 0, 4],
        [2, 3, 0]]])

In [84]: out[1]
Out[84]: 
array([[[8, 3, 3],
        [0, 0, 2]],

       [[8, 5, 4],
        [3, 4, 6]]])