[英]Coverage of the 99% Confidence Interval of a Binomial Proportion
I have an rpy2 script that gives me the coverage of the 95% confidence interval:我有一个 rpy2 脚本,它可以覆盖 95% 的置信区间:
from rpy2.robjects.packages import importr
binom = importr('binom')
from rpy2 import robjects
robjects.r('''library(binom)
p = seq(0,1,.01)
coverage = binom.coverage(p, 10, method="bayes", type = "central")$coverage
''')
I'd like to get the coverage of the 99% confidence interval please我想得到 99% 置信区间的覆盖率
Maybe this way?也许这样?
robjects.r('''library(binom)
p = seq(0,1,.01)
coverage = binom.coverage(p, 10, conf.level = 0.99,
method="bayes", type = "central")$coverage
''')
See documentation .请参阅文档。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.