Regex Java String Split by Asterisk

Question

Help is needed.

line.split("*");

I used this line of code to split a string into an asterisk mark. However, I got an error from my compiler. It says, "INVALID REGULAR EXPRESSION: DANGLING META CHARACTER '*'"

How to resolve this problem? Thanks in advance.

Answer 1

* has special meaning in regular expressions. You have to escape it.

line.split("\\*");

Answer 2

试试这个语句：

line.split("\\*");

Answer 3

It is because you used a "*", that is a regular expression. If you want to use this caracter, you need tu put something like that:

line.split("\\*");

Answer 4

* is a meta character in regular expression. It is used for matching 0 or more elements. If you want to use * as a normal character and not as a special character (ie skip its behavior as a meta character) then add escape characters before it.

Eg: String[] split = line.split("\\\\*");

Hope this helps.

Answer 5

As shown in the following table , * has a special meaning, zero or more times .

Greedy	Reluctant	Possessive	Meaning
X?	X??	X?+	X, once or not at all
X*	X*?	X*+	X, zero or more times
X+	X+?	X++	X, one or more times
X{n}	X{n}?	X{n}+	X, exactly n times
X{n,}	X{n,}?	X{n,}+	X, at least n times
X{n,m}	X{n,m}?	X{n,m}+	X, at least n but not more than m times

Therefore, you need to escape it with a \ . However, \ too is a special character and therefore you need to put an additional \ to escape \ . Thus, the required pattern becomes \\* .

String[] arr = line.split("\\*");
System.out.println(java.util.Arrays.toString(arr));

Answer 6

Use this

" String data= "Mani*Kum";

String []value= data.split("\\*");

" The output will like this:

value[0]= "Mani";
value[1]= "Kum";