I have a variable s
which is a string, and a list of ints called l
. What is the quickest way to add s
to the front of l
and convert the end result of that concatenation
into a tuple?
This is working for me:
l.insert(0, s)
t = tuple(l)
Is there a better way?
Concatenate them:
t = (s,) + tuple(l)
Insertion in front of the list would alter the list itself, and requires looping over the whole list twice (once for insertion, moving the rest of the list up 1 step, once for creating the tuple).
使用生成器表达式构造结果,该表达式一次遍历列表,并且不需要最终串联:
t = tuple(l[i] if i > -1 else s for i in xrange(-1, len(l)))
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