strcpy c++ cannot convert parameter 1 from string char*

Question

i am trying to put the words that there are in a txt file* into an array of strings. But there is an error with the strcpy(). it sais: 'strcpy' : cannot convert parameter 1 from 'std::string' to 'char *' . Why is that? Isn't it possible to create an array of strings like this in c++?

#include <iostream>
#include <fstream>
#include <string>
using namespace std;

void ArrayFillingStopWords(string *p);

int main()
{
   string p[319];//lekseis sto stopwords
   ArrayFillingStopWords(p);
   for(int i=0; i<319; i++)
   {
       cout << p[i];
   }
   return 0;
}

void ArrayFillingStopWords(string *p)
{
    char c;
    int i=0;
    string word="";
    ifstream stopwords;
    stopwords.open("stopWords.txt");
    if( stopwords.is_open() )
    {
       while( stopwords.good() )
       {
           c = (char)stopwords.get();
           if(isalpha(c))
           {
               word = word + c;
           }
           else
           {
               strcpy (p[i], word);//<---
               word = "";
               i++;
           }
       }
   }
   else
   {
       cout << "error opening file";
   }
   stopwords.close();
}

Answer 1

I suggest strcpy (p[i], word); be changed to p[i] = word; . This is the C++ way of doing things and takes advantage of the std::string assignment operator.

Answer 2

You don't need strcpy here. A simple assignment will do it: p[i] = word; . strcpy is for C-style strings, which are null-terminated arrays of characters:

const char text[] = "abcd";
char target[5];
strcpy(target, text);

Using std::string means you don't have to worry about getting the size of the array right, or about calling functions like strcpy .