Replace non-numeric with empty string

Question

Quick add on requirement in our project. A field in our DB to hold a phone number is set to only allow 10 characters. So, if I get passed "(913)-444-5555" or anything else, is there a quick way to run a string through some kind of special replace function that I can pass it a set of characters to allow?

Regex?

Answer 1

Definitely regex:

string CleanPhone(string phone)
{
    Regex digitsOnly = new Regex(@"[^\d]");   
    return digitsOnly.Replace(phone, "");
}

or within a class to avoid re-creating the regex all the time:

private static Regex digitsOnly = new Regex(@"[^\d]");   

public static string CleanPhone(string phone)
{
    return digitsOnly.Replace(phone, "");
}

Depending on your real-world inputs, you may want some additional logic there to do things like strip out leading 1's (for long distance) or anything trailing an x or X (for extensions).

Answer 2

You can do it easily with regex:

string subject = "(913)-444-5555";
string result = Regex.Replace(subject, "[^0-9]", ""); // result = "9134445555"

Answer 3

您不需要使用正则表达式。

phone = new String(phone.Where(c => char.IsDigit(c)).ToArray())

Answer 4

Here's the extension method way of doing it.

public static class Extensions
{
    public static string ToDigitsOnly(this string input)
    {
        Regex digitsOnly = new Regex(@"[^\d]");
        return digitsOnly.Replace(input, "");
    }
}

Answer 5

在.NET中使用Regex方法，您应该可以使用\\ D匹配任何非数字数字，如下所示：

phoneNumber  = Regex.Replace(phoneNumber, "\D", "");

Answer 6

How about an extension method that doesn't use regex.

If you do stick to one of the Regex options at least use RegexOptions.Compiled in the static variable.

public static string ToDigitsOnly(this string input)
{
    return new String(input.Where(char.IsDigit).ToArray());
}

This builds on Usman Zafar's answer converted to a method group.

Answer 7

for the best performance and lower memory consumption , try this:

using System;
using System.Diagnostics;
using System.Text;
using System.Text.RegularExpressions;

public class Program
{
    private static Regex digitsOnly = new Regex(@"[^\d]");

    public static void Main()
    {
        Console.WriteLine("Init...");

        string phone = "001-12-34-56-78-90";

        var sw = new Stopwatch();
        sw.Start();
        for (int i = 0; i < 1000000; i++)
        {
            DigitsOnly(phone);
        }
        sw.Stop();
        Console.WriteLine("Time: " + sw.ElapsedMilliseconds);

        var sw2 = new Stopwatch();
        sw2.Start();
        for (int i = 0; i < 1000000; i++)
        {
            DigitsOnlyRegex(phone);
        }
        sw2.Stop();
        Console.WriteLine("Time: " + sw2.ElapsedMilliseconds);

        Console.ReadLine();
    }

    public static string DigitsOnly(string phone, string replace = null)
    {
        if (replace == null) replace = "";
        if (phone == null) return null;
        var result = new StringBuilder(phone.Length);
        foreach (char c in phone)
            if (c >= '0' && c <= '9')
                result.Append(c);
            else
            {
                result.Append(replace);
            }
        return result.ToString();
    }

    public static string DigitsOnlyRegex(string phone)
    {
        return digitsOnly.Replace(phone, "");
    }
}

The result in my computer is:
Init...
Time: 307
Time: 2178

Answer 8

I'm sure there's a more efficient way to do it, but I would probably do this:

string getTenDigitNumber(string input)
{    
    StringBuilder sb = new StringBuilder();
    for(int i - 0; i < input.Length; i++)
    {
        int junk;
        if(int.TryParse(input[i], ref junk))
            sb.Append(input[i]);
    }
    return sb.ToString();
}

Answer 9

try this

public static string cleanPhone(string inVal)
        {
            char[] newPhon = new char[inVal.Length];
            int i = 0;
            foreach (char c in inVal)
                if (c.CompareTo('0') > 0 && c.CompareTo('9') < 0)
                    newPhon[i++] = c;
            return newPhon.ToString();
        }