How would I get a double value from boost::chrono::steady_clock::now()? I don't believe there is a .count() parameter for this.
Why do I need this? I have a method that cannot parse the boost return.
boost::chrono::steady_clock::now()
returns a boost::chrono::time_point
. boost::chrono::time_point
has a time_since_epoch
method which returns a boost::chrono::duration
. boost::chrono::duration
has a count
method that gives you a scalar. When we put it all together, it boils down to:
auto now = boost::chrono::steady_clock::now().time_since_epoch();
auto timeSinceEpoch = boost::chrono::duration_cast<boost::chrono::milliseconds>(now).count();
Granted that's not a double
but close enough: you can change the duration_cast
to get whatever precision you need and/or divide the timeSinceEpoch
to your liking so that your double
fits your requirements. For example:
// Days since epoch, with millisecond (see duration_cast above) precision
double daysSinceEpoch = double(timeSinceEpoch) / (24. * 3600. * 1000.);
you can specify double
inside duration
:
auto some_time = std::chrono::high_resolution_clock::now();
double duration = std::chrono::duration_cast<std::chrono::duration<double>>(some_time).count();
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