How would I use sed to search for the regex "pk": [0-9]+
in stdin and replace it with "pk": null
?
eg convert "pk": 123
to "pk": null
I've tried something like:
cat mydata.json | sed -e s/\"pk\"\:\s[0-9]+/\"pk\"\:\snull/g
but this has no effect. Cutting the regex back, it seems to break at [0-9]+
but I'm not sure why as this is both a simple and valid regular expression. What am I doing wrong?
这应该工作:
sed -e 's/"pk": [0-9]\+/"pk": null/g' mydata.json
the cat is not necessary.
sed 's/\(.*:\s*\)[0-9]\+/\1null/' file
if you need exactly pk
:
sed 's/\("pk":\s*\)[0-9]\+/\1null/' file
eg
kent$ echo '"pk": 123'|sed 's/\(.*:\s*\)[0-9]\+/\1null/'
"pk": null
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