String array cannot be resolved as variable

Question

Is it possible in Java to redefine value after it already been defined(Like in JavaScript)? Take a look at my sample code, I am trying to redefine String array.

    public String[] checkIfLengEnglish (){
        String language =  Locale.getDefault().getDisplayLanguage() ;
        String LG = Locale.getDefault().getLanguage();

        if(LG.contains("en")){
            String language[] = {"English"}; // Redefining
        }
        else {
            String Language[] = {"English/"+ Language,Language,"English"}; // Redefining
        }

        return Language[];
    }

Answer 1

1. you re-define Language in your code with multiple types at multiple scopes (once at the method level, twice in the if-block/else-block). Don't do that.
2. You don't need to add the [] to reference an array variable, don't do that.

3. Since you declare the array inside the if-block, it only exists inside the if-block. To fix this, you need to declare it outside:

    String[] languages; if( LG.contains("en")){ languages = new String[] {"English"}; }else { languages = new String[] {"English/"+ Language,Language,"English"}; } return languages; 

   Since you no longer use initalization (which can only happen when you declare a variable) but assignment, you need to use the "long form" for specifying the array values, which includes new String[] .

Also note that as a general guideline, method and variable names should start with a lower-case letter and class/interface/enum names should start with a capital letter. That's not technically required, but following this guideline will make your code easier to understand for others.

Answer 2

Language[] is defined inside your if/else statement. You should try putting it above that like

String[] array = new String[];

   if(true){
       array = {"English"};
   }

   return array;

// dummy example

Answer 3

just reframing your code & variables for better understanding purpose

public String[] CheckIfLengEnglish (){
    String displayLanguage =  Locale.getDefault().getDisplayLanguage() ;
    String LG = Locale.getDefault().getLanguage();
    String arrayLanguages[];
    if( LG.contains("en")){
        arrayLanguages = {"English"};
        }else {
        arrayLanguages = {"English/"+ Language,Language,"English"};
    }
    return arrayLanguages ;
}

Answer 4

String[] Language=new String[];

if {

Language={"English"}

}

else {

String Language[] = {"English/"+ Language,Language,"English"}; }

return Language[] ;