I want to filter out messages from a log file that contain eg the sentence This is message 12345. Ignore.
If I would use grep, I could simple pass the sentence and use the -v
switch, for example:
grep -v "This is message 12345\. Ignore\." data.log
The thing is, I have to do this in Python. Something like:
import re
with open("data.log") as f:
data = f.read()
# This will select all lines that match the given sentence
re.findall(".*This is message 12345\. Ignore\..*$", data)
# HERE --> I would like to select lines that DO NOT match that sentence
# ???
I've tried to use (?...)
and [^...]
syntax (see here ), but I couldn't get it right.
Any ideas?
Use a negative lookahead assertion like this:
re.findall("(?!^.*This is message 12345\. Ignore\..*$).*", data)
and also enable the m
modifier, so that ^
and $
match the start and the end of a row.
A simpler method to consider is to convert this to a positive matching problem:
In general, negative matches with regexes get quite complicated. It is usually easier and more efficient to use a positive match to find the things you don't want, and then exclude those things with programming logic.
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.