Char array with cin.getline()

Question

I'm doing an assignment where we aren't allowed to use strings, we have to use char arrays. This is my code:

cout << "Enter Album name: ";
cin >> CDdata[count].title;     
fout << CDdata[count].title;

the problem is that when I enter something with a space in it, the rest of my code gets screwed up.

How do I get it so that I can enter something with a space in it?

Answer 1

Use cin.getline(CDdata[count].title, 1000) . The second parameter is the length of your char array, CData[count].title .

The above function either reads 1000 characters or until it finds a delimiter, which is by default a newline ( \\n ) but can be changed as follows.

 cin.getline(CDdata[count].title, 1000, ',') //delimiter is changed to ','

If you want a more formal description, read here .

PS: I have used 1000, second argument, as a placeholder. You should change it accordingly.

Answer 2

使用cin.getline()因为它将'\\n'作为终止字符而不是空格。

Answer 3

when cin.getline() is escaping some thing its bc of some previous data in buffer that we can clean by cin.ignore() it escape the first caracter while reading from buffer