I have a question about unsigned ints. I would like to convert my unsigned int into a char array. For that I use itoa. The problem is that itoa works properly with ints, but not with unsigned int (the unsigned int is treaded as a normal int). How should I convert unsigned int into a char array?
Thanks in advance for help!
using stringstream is a common approach:
#include<sstream>
...
std::ostringstream oss;
unsigned int u = 598106;
oss << u;
printf("char array=%s\n", oss.str().c_str());
Update since C++11 there is std::to_string() method -:
#include<string>
...
unsigned int u = 0xffffffff;
std::string s = std::to_string(u);
You can simply Make your own function like this one :
Code Link On Ideone using OWN Function
#include<iostream>
#include<cstdio>
#include<cmath>
using namespace std;
int main()
{
unsigned int num,l,i;
cin>>num;
l = log10(num) + 1; // Length of number like if num=123456 then l=6.
char* ans = new char[l+1];
i = l-1;
while(num>0 && i>=0)
{
ans[i--]=(char)(num%10+48);
num/=10;
}
ans[l]='\0';
cout<<ans<<endl;
delete ans;
return 0;
}
You can also use the sprintf
function (standard in C)
sprintf(str, "%d", a); //a is your number ,str will contain your number as string
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.